1 mile at 12 m/h is .2 m/min
1 mile at .2 m/min (1/.2) = 5 min So the first mile took 5 minutes
To find how fast the second mile was:
You know it was 1 mile and it took 10 minutes
1/10=.1 m/min which is 6 m/h
The average speed is 6+12/2=9 m/h
Hope that helps. Feel free to ask any questions.
Answer:
Patient A - 150 mg
Patient B - 50 mg
Step-by-step explanation:
Since patient A gets three times more, 50 times 3 is 150. 150 plus 50 is 200, therefore, patient A gets 150 mg and patient B gets 50 mg. I hope this helps :)
Y=20x+120
y=30x
30x=20x+120
30x-20x=120
10x=120
x=12 days
y=30x
y=30(12)
y=360 minutes
Answer: the gun was held 4ft high i.e H = 4ft
Step-by-step explanation:
To determine how high the gun was held when it was fired H;
Before firing the t-shirt up, the gun and the t-shirt are both at the same height.
Therefore,
H = h(0) i.e h(t) at t = 0
h(t) = -16t^2 + 64t + 4
H = h(0) = -16(0)^2 + 64(0) + 4
H = 4ft
Answer: The value of x- 2y is a. 
.
Step-by-step explanation:
Given: x and y are two positive real numbers such that 
and 
.
Consider ![(x-2y)^2=x^2-2(x)(2y)+(2y)^2\ \ \ [(a+b)^2=(a^2-2ab+b^2)]](https://tex.z-dn.net/?f=%28x-2y%29%5E2%3Dx%5E2-2%28x%29%282y%29%2B%282y%29%5E2%5C%20%5C%20%5C%20%5B%28a%2Bb%29%5E2%3D%28a%5E2-2ab%2Bb%5E2%29%5D)
Put and , we get
Taking square root on both sides , we get'
Hence, the value of x- 2y is a. .
