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Minchanka [31]
2 years ago
9

The cost for making a telephone call from Vero beach to Miami is 37 cents for The first 3 minutes and 9 cents per each additiona

l minute. There is a 10% discount for call placed after 10pm. what is the cost of a 10 minute telephone call at placed at 11pm? Round your answer to the nearsest cent.
Mathematics
2 answers:
Evgen [1.6K]2 years ago
7 0

Answer:90cents

Cost of a  10 minute call before 10pm:

37 cents + 9cents*7minutes = 37 cents+63 cents =100 cents

10% of 100cents:

100*10/100= 10 cents

Cost of  the call after 10 pm (i.e with a 10% discount)

100-10= 90 cents

Vinvika [58]2 years ago
4 0

Answer:

  $0.90

Step-by-step explanation:

A 10-minute call exceeds the 3-minute initial period by 7 minutes. The initial period charge is 37¢. The additional minute charge is 7·9¢ = 63¢. Then the regular charge for that call is ...

  37¢ +63¢ = 100¢ = $1.00

The 10% discount reduces the charge by ...

  10% × $1.00 = $0.10

so the final cost of the 10-minute call is ...

  $1.00 -0.10 = $0.90 . . . . . cost of the call

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[Q71 Suppose that the height, in inches, of a 25-year-old man is a normal random variable with parameters g = 71 inch and 02 = 6
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Answer: (a) Percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

              (b) Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

Step-by-step explanation:

Given that,

                  Height (in inches) of a 25 year old man is a normal random variable with mean g=71 and variance o^{2} =6.25.

To find:  (a) What percentage of 25 year old men are 6 feet, 2 inches tall

               (b) What percentage of 25 year old men in the 6 footer club are over 6 feet. 5 inches.

Now,

(a) To calculate the percentage of men, we have to calculate the probability

P[Height of a 25 year old man is over 6 feet 2 inches]= P[X>74in]

                           P[X>74] = P[\frac{X-g}{o} > \frac{74-71}{2.5}]

                                         = P[Z > 1.2]

                                         = 1 - P[Z ≤ 1.2]

                                         = 1 - Ф (1.2)

                                         = 1 - 0.8849

                                         = 0.1151

Thus, percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) P[Height of 25 year old man is above 6 feet 5 inches gives that he is above 6 feet] = P[X, 6ft 5in - X, 6ft]

     P[X > 6ft 5in I X > 6ft] = P[X > 77 I X > 72]

                                          = \frac{P[X > 77]}{P[ X > 72]}

                                          = \frac{P[\frac{X - g}{o}>\frac{77-71}{2.5}]  }{P[\frac{X-g}{o} >\frac{72-71}{2.5}] }

                                          = \frac{P[Z >2.4]}{P[Z>0.4]}

                                          =  \frac{1-P[Z\leq2.4] }{1-P[Z\leq0.4] }

                                          = \frac{1-0.9918}{1-0.6554}

                                          = \frac{0.0082}{0.3446}

                                          = 0.024

Thus, Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

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