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iragen [17]
2 years ago
9

The base of pyramid A is a rectangle with a length of 10 meters and a width of 20 meters. The base of pyramid B is a square with

10-meter sides. The heights of the pyramids are the same. The volume of pyramid A is the volume of pyramid B. If the height of pyramid B increases to twice that of pyramid A, the new volume of pyramid B is the volume of pyramid A.
Mathematics
2 answers:
drek231 [11]2 years ago
5 0

first is twice

second equal to

ollegr [7]2 years ago
4 0
Given:
Pyramid A: Base is rectangle with length of 10 meters and width of 20 meters.
Pyramid B: Base is square with 10 meter sides.
Heights are the same.

Volume of rectangular pyramid = (L * W * H) / 3
Volume of square pyramid = a² * h/3

Let us assume that the height is 10 meters.
V of rectangular pyramid = (10m * 20m * 10m)/3 = 2000/3 = 666.67 m³
V of square pyramid = (10m)² * 10/3 = 100m² * 3.33 = 333.33 m³

The volume of pyramid A is TWICE the volume of pyramid B.

If the height of pyramid B increases to twice the of pyramid A, (from 10m to 20m),  

V of square pyramid = (10m)² * (10*2)/3 = 100m² * 20m/3 = 100m² * 6.67m = 666.67 m³

The new volume of pyramid B is EQUAL to the volume of pyramid A.
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bearhunter [10]

Answer: If I am correct the value of x might be f=0

Step-by-step explanation:

5 0
2 years ago
For the diagram below figure b is a reflection of y=2x of the line y =x
Scilla [17]
The equation of the line would be y = (1/2)x.

To find the equation of a line that is reflected through the line y = x, we just switch the x and y. Then, solve for y.

y = 2x
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2 years ago
Now let the figure show a scale drawing of a park. The scale is 1 unit : 25 meters. What is the horizontal distance across the p
insens350 [35]

The question is missing the figure. So, the figure is attached below.

Answer:

C. 350 m

Step-by-step explanation:

Given:

Scale  is given as:

1 unit  : 25 meters

This means that 1 unit on the grid is equivalent to 25 meters in actual.

Now, from the figure, the horizontal distance across the park is 14 units.

1 unit = 25 meter

Now, we can find the actual distance using unitary method and thus multiplying 25 and 14 to get the actual distance across the park horizontally.

∴ 14 units = 25\times 14=350 meters.

Therefore, the horizontal distance across the park is 350 m in actual.

So, the correct option is option C.

7 0
2 years ago
Two galaxies are shown. Galaxy U: Dust, gas, and stars in the shape of a pinwheel, relatively small in size. Galaxy NGC 1427A: D
Pani-rosa [81]

Answer:

NGC 1427A has no general shape, so it is an irregular galaxy. U has a bulge in the center and arms, so it is a spiral galaxy. They are similar in that both contain plenty of dust and gas. Both also have active star-forming sites.

Step-by-step explanation: Got it right on the test

8 0
2 years ago
Read 2 more answers
Emma was about to finish grocery shopping when she noticed that cans of soup were on sale. Her total bill for groceries would be
Alinara [238K]

Answer:

3rd option: B(C)= 1.79C +86.03

Step-by-step explanation:

Total bill

= cost of cans(number of cans) +cost of other groceries

Let the cost of other groceries be G, and the cost of cans be X.

Given that number of cans= C,

Total bill= XC +G

If 2 cans were purchased,

2X+G= 89.61 -----(1)

If 5 cans were purchased,

5X +G= 94.98 -----(2)

(2) -(1):

(5X +G) -(2X +G)= 94.98 -89.61

5X +G -2x -G= 5.37

3X= 5.37

X= 5.37 ÷3 <em>(</em><em>÷</em><em>3</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

X= 1.79

Subst. X= 1.79 into (1):

2(1.79) +G= 89.61

3.58 +G= 89.61

G= 89.61 -3.58 <em>(</em><em>-3.58</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

G= 86.03 <em>(</em><em>simplify</em><em>)</em>

Total bill

= XC +G

= 1.79C +86.03

Thus, the function is B(C)= 1.79C +86.03.

3 0
2 years ago
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