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iragen [17]
2 years ago
9

The base of pyramid A is a rectangle with a length of 10 meters and a width of 20 meters. The base of pyramid B is a square with

10-meter sides. The heights of the pyramids are the same. The volume of pyramid A is the volume of pyramid B. If the height of pyramid B increases to twice that of pyramid A, the new volume of pyramid B is the volume of pyramid A.
Mathematics
2 answers:
drek231 [11]2 years ago
5 0

first is twice

second equal to

ollegr [7]2 years ago
4 0
Given:
Pyramid A: Base is rectangle with length of 10 meters and width of 20 meters.
Pyramid B: Base is square with 10 meter sides.
Heights are the same.

Volume of rectangular pyramid = (L * W * H) / 3
Volume of square pyramid = a² * h/3

Let us assume that the height is 10 meters.
V of rectangular pyramid = (10m * 20m * 10m)/3 = 2000/3 = 666.67 m³
V of square pyramid = (10m)² * 10/3 = 100m² * 3.33 = 333.33 m³

The volume of pyramid A is TWICE the volume of pyramid B.

If the height of pyramid B increases to twice the of pyramid A, (from 10m to 20m),  

V of square pyramid = (10m)² * (10*2)/3 = 100m² * 20m/3 = 100m² * 6.67m = 666.67 m³

The new volume of pyramid B is EQUAL to the volume of pyramid A.
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R+5/mn=p solve for m
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Answer:

               \bold{m\ =\ \dfrac5{(p-r)n}}

Step-by-step explanation:

                                             \bold{r+\dfrac5{mn}\ =\ p}\\\\ {}\quad-r\qquad-r\\\\{}\ \ \bold{\dfrac5{mn}\ =\ p-r}\\\\{}\ ^{_\times}(mn)\quad ^{_\times}(mn)\\\\{}\quad\bold{5\ =\ (p-r)^{_\times}(mn)}\\\\\div(p-r)\quad\div(p-r)\\\\{}\ \ \bold{\dfrac5{p-r}\ =\ mn}\\\\{}\quad \ \div n\quad\ \ \div n\\\\\bold{\dfrac5{(p-r)n}\ =\ m}

If you mean (r+5)/mn then:

\bold{\dfrac{r+5}{mn}\ =\ p}\\\\{}\ ^{_\times}(mn)\quad ^{_\times}(mn)\\\\{}\ \bold{r+5\ =\ pmn}\\\\\div(pn)\quad\div(pn)\\\\{}\ \ \bold{\dfrac{r+5}{pn}\ =\ m}

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A standard city block in Manhattan is a rectangle measuring 80 m by 270 m. A resident wants to get from one corner of a block to
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68.4 meters shorter

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ok so you want to compare the distance  80 m + 270 m with the diagonal length.

the diagonal length =  root ( 80^2   +  270^2 )

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350 - 281.602 = 68.397 meters  about  68.4 meters  shorter than walking around

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2 years ago
12. Venu and Tanuj are running along a circular track. They take 48 seconds and 56 seconds to
brilliants [131]

Answer:

The meet at first time at starting point after 336 seconds,

Vanu have completed 7 laps while Tanuj has completed 6 laps.

Step-by-step explanation:

Given that Venu and Tanuj take 48 seconds and 56 seconds to

complete a lap respectively.

To meet them again at the startiong point, the  time taken must be multiple of 56 and 48.

So, the minimum time required to meet them again at the startiong point is time taken for first time meet.

Time taken to first time meet is the smallest number which can be divided by 56 and 48, i.e the lowest common factor (LCM) of 56 and 48 which is 336 seconds or 5 minutes 36 seconds.

Number of laps by Venu

=\frac{336}{48}=7

Number of laps by Tanuj

=\frac{336}{56}=6

8 0
2 years ago
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