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drek231 [11]
2 years ago
13

You want to make five-letter codes that use the letters A, F, E, R, and M without repeating any letter. What is the probability

that a randomly chosen code starts with M and ends with E?
Mathematics
1 answer:
Feliz [49]2 years ago
4 0

Answer:

The probability that a randomly chosen code starts with M and ends with E is 0.05 ....

Step-by-step explanation:

According to the given statement we have to make five letter code from  A, F, E, R, and M without repeating any letter. We have to find that what is probability that a randomly chosen code starts with M and ends with E.

Thus the probability of picking the first letter M = 1/5

After that we require the sequence (not E, not E, not E) which is equal to:

= 3/4 * 2/3* *1/2

= 1/4

Now multiply 1/5 and 1/4

1/5 * 1/4

= 1/20

= 0.05

Therefore the probability that a randomly chosen code starts with M and ends with E is 0.05 ....

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Let the distance of the first part of the race be x, and that of the second part, 15 - x, then
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Therefore, the distance of the first part of the race is 5 miles and the time is 5/8 = 0.625 hours or 37.5 minutes
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This is the concept of sinusoidal, to solve the question we proceed as follows;
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We have,

U = { (x,y) : x,y belong to real numbers }

A = { (x,y) : (x,y) is a solution of y=x }

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We need to find the ordered pair (x,y) that belong to A\bigcapB.

Let, (x,y) belong to A\bigcapB

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Answer:

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Step-by-step explanation:

The given equation is:

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