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drek231 [11]
2 years ago
13

You want to make five-letter codes that use the letters A, F, E, R, and M without repeating any letter. What is the probability

that a randomly chosen code starts with M and ends with E?
Mathematics
1 answer:
Feliz [49]2 years ago
4 0

Answer:

The probability that a randomly chosen code starts with M and ends with E is 0.05 ....

Step-by-step explanation:

According to the given statement we have to make five letter code from  A, F, E, R, and M without repeating any letter. We have to find that what is probability that a randomly chosen code starts with M and ends with E.

Thus the probability of picking the first letter M = 1/5

After that we require the sequence (not E, not E, not E) which is equal to:

= 3/4 * 2/3* *1/2

= 1/4

Now multiply 1/5 and 1/4

1/5 * 1/4

= 1/20

= 0.05

Therefore the probability that a randomly chosen code starts with M and ends with E is 0.05 ....

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If George is 33 1/3% richer than Pete, than Pete is what percent poorer than George?
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Answer:

25%

Step-by-step explanation:

George is 33\frac{1}{3}% (\frac{100}{3}%) richer than Pete. Let Pete's percentage of wealth be 100%.

Thus George percentage of wealth = 100% + \frac{100}{3}%

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Pete's percent poorer than George can be determined by;

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The diameter of Circle C is 4.
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Step-by-step explanation:

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