You want to make five-letter codes that use the letters A, F, E, R, and M without repeating any letter. What is the probability
1 answer:
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Answer:
Step-by-step explanation:
Given is a differential equation of III order,
The characteristic equation would be cubic as
By trial and error, we find that
Thus m=2 is one solution
Since given that is one solution we get
m = -4+i and hence other root is conjugate
Hence general solution would be
Answer:
Option C and E are correct.
The sequences which are arithmetic:
18, 5.5, -7, -19.5, -32,....
16, 32, 48, 64, 80
Step-by-step explanation:
Arithmetic sequence states that a sequence in which a common difference between each consecutive term is constant.
Common difference(d) = for every natural number n.
Option A:
-5, 5, -5, 5, -5, .....
5-(-5) = 5+5 = 10 ,
-5 -5 = -10 .....
Since, the common difference for the given sequence is not constant.
Option B:
96, 48, 24, 12, 6
48 -96 = -48
24-48 = -24 ....
Common difference for the given sequence is not constant.
Option C:
18, 5.5, -7, -19.5, -32,....
5.5-18 = -12.5
-7 -5.5 = -12.5 ....
∴Common difference for the sequence is constant.
Option D:
-1, -3, -9, -27, -81 ,....
-3 -(-1) = -3+1 = -2
-9-(-3) = -9+3 = -6 ....
∴Common difference for the sequence is not constant.
Option E:
16, 32, 48, 64, 80
32-16 = 16
48 - 32 = 16 and so on...
∴Common difference for the sequence is constant.
Therefore, the sequences which are arithmetic are:
18, 5.5, -7, -19.5, -32,....
16, 32, 48, 64, 80