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densk [106]
2 years ago
10

Which situation is best modeled by the inequality g ≤ 13?

Mathematics
1 answer:
Olin [163]2 years ago
8 0

Answer:

You must be no older than 13 to play a game.

Step-by-step explanation:

≤ this sign means equal to or less than in this case it is 13

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You have a budget of $48. You want to buy fruit and granola bars. Fruit costs $4 per pound, and the granola bars are $1 each. Yo
zzz [600]

1)Define the variables you will use in your model.

Let

x------->total pounds of the fruit

y-------> the total number of granola bars

TC----> total cost

Tf------> total cost of the fruit

Tg----> total cost of the granola bars

2) Write an inequality representing the total cost of your purchase. (3 points)

a. Each pound of fruit costs $4. Write an expression that shows the total cost of the fruit. Use the variable you identified in question 1

Tf=4*x

b. Each granola bar costs $1. Write an expression that shows the total cost of the granola bars. Use the variable you identified in question 1.

Tg=1*y--------> Tg=y

c. Combine the expressions from parts a and b to write an expression for the total cost. Then use this expression to write an inequality that compares the total cost with the amount you have to spend.

TC=Tf+Tg

TC=4*x+y

inequality-------> 4x+y \leq 48

3. Write the inequality that models the number of granola bars you need to buy.

You need at least 10 granola bars

so

y\geq 10

4. Describe in words what each of your inequalities means

inequality 1

4x+y \leq 48

the total cost of fruits plus the total cost of granola bars must be less than or equal to 48 dollars

inequality 2

y\geq 10

5. Graph your system of inequalities.

using a graph tool

see the attached figure

6. Identify one point on the graph that represents a viable solution to the problem, and then identify one point that does not represent a viable solution.

Let

A-------> one point on the graph that represents a viable solution

B-------> one point on the graph that does not represent a viable solution

A(4,20)

x=4-------> total pounds of the fruit

y=20------> the total number of granola bars

check point A

substitute the values of x and y in the inequality 1

4x+y \leq 48

4*4+20\leq 48\\ 36\leq 48-------> is ok

substitute the values of x and y in the inequality 2

y\geq 10

20\geq 10--------> is ok

the point A represents a viable solution, because satisfies both inequalities

B(10,30)

x=10-------> total pounds of the fruit

y=30------> the total number of granola bars

check point B

substitute the values of x and y in the inequality 1

4x+y \leq 48

4*10+30\leq 48\\ 70\leq 48-------> is not a viable solution

substitute the values of x and y in the inequality 2

y\geq 10

30\geq 10--------> is ok

the point B is not a viable solution because does not satisfy the inequality 1

3 0
1 year ago
A radio station receives 3815 phone calls in 35 min. How many calls does it get in 1 hr? Show Your Work.
Hatshy [7]
In 1 min it receives 3815/35=109 so in 1 hour it receives 109x60=6540 calls
8 0
2 years ago
Question 1(Multiple Choice Worth 1 points)
tester [92]

The correct answer is d15

7 0
1 year ago
2 groups of 10 tiles and 2 groups of 3 tiles. Which explains whether or not this model accurately shows 26 ÷ 2? It does because
WINSTONCH [101]

Answer:

It does because 26 = 20 + 6, and the model shows 2 groups of 10 and 2 groups of 3.  

Step-by-step explanation:

Two groups of 10 make 20. Two groups of 3 make 6.

20 + 6 = 26

B is wrong. The model does not show two groups of 6.

C is wrong. The model should show one group of 6..

D is wrong. The model should show two groups of 10 and one group of 6.

7 0
2 years ago
In a study in Scotland (as reported by Devlin 2009), researchers left a total of 320 wallets around Edinburgh, as though the wal
Ann [662]

Answer:

a) The observed proportion of wallets that were returned

  p = 0.45625

b) <em> 95% of confidence intervals for Population proportion</em>

<em>  0.40168  , 0.51082)</em>

<em>c) The lower bound of the 95% confidence interval = 0.40168</em>

<em>d) The upper bound of the 95% confidence interval = 0.51082</em>

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

a)

Given data the  researchers left a total of 320 wallets around Edinburgh, as though the wallets were lost. Each contained contact information including an address. Of the wallets, 146 were returned by the people who found them

Given sample size 'n' = 320

  Given data          'x ' = 146

<em>Sample proportion </em>

              p = \frac{x}{n}

             p = \frac{x}{n} = \frac{146}{320} = 0.45625

<u><em>Step(ii)</em></u>:-

b)<em> </em><u><em>95% of confidence intervals for Population proportion</em></u>

Level of significance = 95% or 0.05%

Z_{\frac{\alpha }{2} } = Z_{\frac{0.05}{2} } = Z_{0.025} = 1.96

<em>95% of confidence intervals for Population proportion are determined by</em>

<em></em>(p - Z_{0.025} \frac{\sqrt{p(1-p)} }{\sqrt{n} } , p + Z_{0.025} \frac{\sqrt{p(1-p)} }{\sqrt{n} })<em></em>

<em></em>(0.45625 - 1.96\frac{\sqrt{0.45625(1-0.45625)} }{\sqrt{320} } , 0.45625 + 1.96\frac{\sqrt{0.45625(1-0.45625)} }{\sqrt{320} })<em></em>

<em>(0.45625 - 0.05457 , 0.45625 + 0.05457)</em>

<em>(   0.40168  , 0.51082) </em>

<em>c) The lower bound of the 95% confidence interval = 0.40168</em>

<em>d) The upper bound of the 95% confidence interval = 0.51082</em>

7 0
2 years ago
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