answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
valentinak56 [21]
1 year ago
6

Suppose you doubt the assumption that the mean age of the stars is 3.3 billion years, but you don't know whether the true mean a

ge is less or greater than 3.3 billion years.
Required:
a. To test whether the population mean is 3.3 billion years, what would your null and alternative hypotheses be?
b. What test will you use, how will the test work, and what are the conditions necessary to use the test? Does your situation meet those conditions?
c. Calculate yoour test statistic and P-value. Show your work, including the formulas you used to calculate the statistic.
Mathematics
1 answer:
svet-max [94.6K]1 year ago
8 0

Answer:

(a) Null Hypothesis, H_0 : \mu = 3.3 billion years      

Alternate Hypothesis, H_A : \mu\neq 3.3 billion years

(b) The conditions necessary to use this test is that the data must follow a normal distribution and we know about the population standard deviation.

(c) The value of z-test statistics is 1.77 and the P-value is 0.0768.

Step-by-step explanation:

<u>The complete question is:</u> A theory predicts that the mean age of stars within a particular type of star cluster is 3.3 billion years, with a standard deviation of 0.4 billion years. (Their ages are approximately normally distributed.) You think the mean age is actually greater, and that this would lend support to an alternative theory about how the clusters were formed. You use a computer to randomly select the coordinates of 50 stars from the catalog of known stars of the type you're studying and you estimate their ages. You find that the mean age of stars in your sample is 3.4 billion years.

Suppose you doubt the assumption that the mean age of the stars is 3.3 billion years, but you don't know whether the true mean age is less or greater than 3.3 billion years.

Let \mu = <u><em>population mean age of the stars</em></u>

(a) Null Hypothesis, H_0 : \mu = 3.3 billion years      {means that the population mean is 3.3 billion years}

Alternate Hypothesis, H_A : \mu\neq 3.3 billion years      {means that the population mean is different from 3.3 billion years, i.e. the true mean age is less or greater than 3.3 billion years}

(b) The test statistics that will be used here is One-sample z-test statistics because we know about the population standard deviation;

                          T.S.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean age of stars = 3.4 billion years

            \sigma = population standard deviation = 0.4 billion years

            n = sample of stars = 50

The conditions necessary to use this test is that the data must follow a normal distribution and we know about the population standard deviation. And the conditions are satisfied here.

(c) <em><u>So, the test statistics</u></em> =  \frac{3.4-3.3}{\frac{0.4}{\sqrt{50} } }

                                         =  1.77

The value of z-test statistics is 1.77.

Also, the P-value of the test statistics is given by;

                P-value = P(Z > 1.77) = 1 - P(Z \leq 1.77)

                              = 1 - 0.9616 = 0.0384

For the two-tailed test, the P-value is calculated as = 2 \times 0.0384 = 0.0768.

You might be interested in
n 2018, homes in East Baton Rouge (EBR) Parish sold for an average of $239,000. You take a random sample of homes in Ascension p
Olenka [21]

Answer:

Conclusion

   There is no sufficient evidence to conclude that the mean of the home prices from Ascension parish is higher than the EBR mean

Step-by-step explanation:

From the question we are told that

   The population mean for EBR is  \mu_ 1  = \$239,000

    The sample mean for Ascension parish  is \= x_2  = \$246,000

   The  p-value  is  p-value  =  0.045

     The level of significance is  \alpha = 0.01

The null hypothesis is  H_o : \mu_2  = \mu_1

The  alternative hypothesis is  H_a  :  \mu_2 > \mu_1

Here \mu_2 is the population mean for Ascension parish

   From the data given values we see that  

          p-value  >  \alpha

So we fail to reject the null hypothesis

So we conclude that there is no sufficient evidence to conclude that the mean of the home prices from Ascension parish is higher than the EBR mean

3 0
1 year ago
Complete the steps for solving 7 = –2x2 + 10x. Factor out of the variable terms. inside the parentheses and on the left side of
Mamont248 [21]

we have

7=-2x^{2} +10x

Factor the leading coefficient

7=-2(x^{2} -5x)

Complete the square. Remember to balance the equation by adding the same constants to each side

7-12.50=-2(x^{2} -5x+2.5^{2})

-5.50=-2(x^{2} -5x+2.5^{2})

Divide both sides by -2

2.75=(x^{2} -5x+2.5^{2})

Rewrite as perfect squares

2.75=(x-2.5)^{2}

Taking the square roots of both sides (square root property of equality)

x-2.5=(+/-)\sqrt{2.75}

Remember that

\sqrt{2.75}=\sqrt{\frac{11}{4}}= \frac{\sqrt{11}}{2}

x-2.5=(+/-)\frac{\sqrt{11}}{2}

x=2.5(+/-)\frac{\sqrt{11}}{2}

x=2.5+\frac{\sqrt{11}}{2}=\frac{5+\sqrt{11}}{2}

x=2.5-\frac{\sqrt{11}}{2}=\frac{5-\sqrt{11}}{2}

<u>the answer is</u>

The solutions are

x=\frac{5+\sqrt{11}}{2}

x=\frac{5-\sqrt{11}}{2}


5 0
1 year ago
Read 2 more answers
Crossett Trucking Company claims that the mean weight of its delivery trucks when they are fully loaded is 6,000 pounds and the
solniwko [45]

Answer:

(5953.52,6046.49)

Step-by-step explanation:

We are given the following in the question:

Mean, \mu = 6,000 pounds

Sample size, n = 40

Alpha, α = 0.05

Standard deviation, σ = 150 pounds

95% Confidence interval:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

6000 \pm 1.96(\dfrac{150}{\sqrt{40}} )\\\\ = 6000 \pm 46.4854=\\(5953.5146,6046.4854)\approx (5953.52,6046.49)

are the limits within which 95% of the sample means occur.

6 0
1 year ago
Maggie has a ribbon 27 feet long.What is the length of the ribbon in yards?
finlep [7]
The ribbon would be 9 yards long
3 0
1 year ago
Read 2 more answers
Given the function f(x) = −3x3 + 9x2 − 2x + 3, what part of the function indicates that the left end starts at the top of the gr
shutvik [7]

Answer: The correct option is, The coefficient of the first term.

Step-by-step explanation:

The given function is,

f(x)=-3x^3+9x^2-2x+3

End behavior of the polynomial function : It is defined as the graph of f(x) as x approaches +\infty and -\infty.

The end behavior of the graph depends on the leading coefficient and degree of the polynomial.

As, the degree of the polynomial is '3'. So, the leading coefficient will determine the structure of the graph.

Therefore, the coefficient of the first term will indicate that the left end starts at the top of the graph.

The graph is also shown below.

5 0
2 years ago
Read 2 more answers
Other questions:
  • The vertex of this parabola is at (-2, -3). When the y-value is -2, the x-value is -5. Determine the coefficient of the squared
    7·1 answer
  • Enya walked 2 km 309 m from school to the store. Then, she walked from the store to her home. If she
    5·1 answer
  • A television camera at ground level is filming the lift-off of a space shuttle at a point 750 meters from the launch pad. Let θ
    11·1 answer
  • If you have 20 square pieces of wood describe all the different ways you could make a rectangle by placing them side-by-side
    8·1 answer
  • A packing crate measures 3 feet by 12 feet by 7 feet. what is the area of its smallest side
    5·1 answer
  • PLEASE HELP NOW 20pts........
    9·2 answers
  • Katie invested $33,750 at 11.17% compounded continuously.
    12·1 answer
  • There are 15 people in a party, including Hannah and Sarah. We divide the 15 people into 3 groups, where each group has 5 people
    6·2 answers
  • Let X, the number of flaws on the surface of a randomly selected boiler of a certain type, have a Poisson distribution with para
    11·1 answer
  • Kellianne lined up the interior angles of the triangle along line p below.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!