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Montano1993 [528]
1 year ago
7

A researcher wants to know how homeowners in her state feel about home warranties. She obtains a list of 879 homeowners in her s

tate, selects 300 of them at random, and emails a questionnaire to them. 64 questionnaires are returned. Of these, 80% stated that they believe that the current home warranty coverage needs to be completely overhauled. Classify the following groups as the population or the sample for this particular study.
a. all homeowners in the researcher's state
b. The 879 homeowners whose names were obtained
c. The 64 homeowners who returned the questionnaire
d. The 80% who stated that the current home warranty coverage needs to be completely overhauled
Mathematics
1 answer:
TEA [102]1 year ago
7 0

Answer:

a. The population

b. The accessible population

c. The sample

d. The statistic

Step-by-step explanation:

a. All the homeowners in the researchers state = The target population

b. The 879 homeowners whose name were obtained = The sample frame (accessible population)

c. The 64 homeowners who returned the questionnaire = Research participants (the sample), the subjects

d. The 80% who stated that the current home warranty coverage needs to be completely overhauled = The statistic (subset or part of the sample)

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The graph shows a fir tree's diameter growth over a 50 year period.
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Camilo practica tiro al blanco. En cada disparo acertado puede obtener 5, 8, o 10 puntos. En su última práctica, su puntuación t
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Answer:

20 disparos

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Primera etapa es de determinar cuantos tiros de Camilo acertaron al blanco.

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5x + 8y + 10x = 99

Sabemos también que el obtuvo tantos tiros de 8 puntos que de 10 puntos, entonces

y = z

Podemos mezclar las 2 ecuaciones y substituir y por z:

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Una ecuación, dos variables... no es fácil... pero son números pequeños y se puede intentar soluciones.  Entonces, cuantas veces podemos multiplicar 5 y 18 para obtener 99?

El más simple es de hacer la tabla de multiplicación de 18 y ver cual número nos deja con un multiple de 5.

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18 x 2 = 36 (99 - 36 = 63, no un multiple de 5)

18 x 3 = 54 (99 - 54 = 45, SI, un multiple de 5)

18 x 4 = 72 (99 - 72 = 27, no un multiple de 5)

18 x 5 = 90 (99 - 90 = 9, no un multiple de 5)

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En total tiró 15 veces.

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\frac{15}{3/4} = \frac{15 * 4}{3} = 20

Camilo tiró 20 veces en total.

8 0
2 years ago
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