Ask question

Ask question

All categories

adelina 88 [10]

2 years ago

9

A rectangle is 5 √7 + 2 √3 meters long and 6 √7 - 3 √3 meters wide. a. Find the perimeter of the rectangle in simplest form. 2 b

. Find the area of the rectangle in simplest form.

1 answer:

Lunna [17]2 years ago

6 0

I think the answer is 16.70

You might be interested in

A random draw is being designed for 210 participants. A single winner is to be chosen, and all the participants must have an equ

Over [174]

Answer: The correct number of balls is (b) 4.

Step-by-step explanation: Given that a single winner is to be chosen in a random draw designed for 210 participants. Also, there is an equal probability of winning for each participant.

We are using 10 balls, numbered through 0 to 9. We are to find the number of balls which needs to be picked up, regardless of order, so that each of the 210 participants can be assigned a unique set of numbers.

Let 'r' represents the number of balls to be picked up.

Since we are choosing from 10 balls, so we must have

$^{10}C_r=210.$

The value of 'r' can be any one of 0, 1, 2, . . , 10.

Now,

if r = 1, then

$^{10}C_1=\dfrac{10!}{1!(10-1)!}=\dfrac{10!}{1!9!}=\dfrac{10\times 9!}{1\times 9!}=10$

If r = 2, then

$^{10}C_2=\dfrac{10!}{2!(10-2)!}=\dfrac{10!}{2!8!}=\dfrac{10\times 9\times 8!}{2\times 1\times 8!}=45$

If r = 3, then

$^{10}C_3=\dfrac{10!}{3!(10-3)!}=\dfrac{10!}{3!7!}=\dfrac{10\times 9\times 8\times 7!}{3\times 2\times 1\times 7!}=120$

If r = 4, then

$^{10}C_4=\dfrac{10!}{4!(10-4)!}=\dfrac{10!}{4!6!}=\dfrac{10\times 9\times 8\times\times 7\times 6!}{4\times 3\times 2\times 1\times 6!}=210.$

Therefore, we need to pick 4 balls so that each participant can be assigned a unique set of numbers.

Thus, (b) is the correct option.

4 0

2 years ago

Read 2 more answers

Determine a series of transformations that would map polygon ABCDE onto<br>polygon A'B'C'D'E'?<br>

vovangra [49]

Answer:

A reflection followed by a translation

Step-by-step explanation:

A reflection across they x-axis would put all the points in the right section and on the right y value. The x value would need to be changed though. So, you would need to do a translation of 4 on all points.

3 0

2 years ago

There were 230{,}600230,600230, comma, 600 jobs available in the field of radiology in the year 201420142014. Each year, that nu

dexar [7]

Answer:

j(t)=230600(1.009)^t

Step-by-step explanation:

Increasing at a rate of 0.9\%0.9%0, point, 9, percent means the expected number of jobs keeps its 100\%100%100, percent and adds 0.9\%0.9%0, point, 9, percent more, for a total of 100.9\%100.9%100, point, 9, percent.

So each year, the expected number of jobs is multiplied by 100.9\%100.9%100, point, 9, percent, which is the same as a factor of 1.0091.0091, point, 009.

If we start with the initial number of jobs, 230{,}600230,600230, comma, 600 jobs, and keep multiplying by 1.0091.0091, point, 009, this function gives us expected number of jobs in radiology ttt years from 201420142014:

j(t)=230600(1.009)^t

6 0

2 years ago

Read 2 more answers

A central angle, thata, of a circle with radius 16 inches intercepts an arc of 19.36 inches. Find thata.

kaheart [24]

Theta*
$\theta=\frac{19.36}{16}=1.21$ radians.

5 0

2 years ago

Read 2 more answers

A triathlon includes a .5 km swim, 40 km bike, and a 10 km run. Mr. B completed the swim in 25 minutes and 10 seconds, and the b

Dmitry_Shevchenko [17]

Answer:

3.33 meters per second

Step-by-step explanation:

you must find the total time that Mr. B spent to complete the swim and bike.

Information:

0h 25' 10'' ---------> Swim

1h 30' 50'' ---------> Bike

$hours = 0 + 1 = 1\\minutes = 25+30 = 55\\seconds = 10+50=60\\$

he spent 1h 55' 60'', this is 1h 56'.

now you must substract this time from the record time to find the time alloted to run:

first you convert both times into minutes:

$record \ time = 2(60) + 46 = 166 \ minutes \ \ \ \ multiply \ hours \ by \ 60 \ minutes\\time\ swim \ and \ bike = 1(60) + 56 = 116 \ minutes\\$

now substracting:

$time \ to \ run \ = record \ time \ - \ time \ swim \ and \ bike\\time \ to \ run \ = 166 - 116 = 50 \ minutes$

so he must travel 10 km in 50 minutes, that is:

speed = distance/time

$speed = \frac{10}{50} \frac{km}{min}$

1 km is equal to 1000 meters and 1 minute is equal to 60 seconds.

$speed = \frac{(10)}{(50)}\frac{(1000) meters}{(60) sec}\\\\speed = \frac{(10000)}{(3000)}\frac{meters}{sec} \ \ \ \ \ \ \ \ \ multiply \\\\speed = 3.33 \ meters/sec$

so Mr.B's speed must be 3.33 meters/sec

8 0

2 years ago