Question

If the pointer in the figure is spun twice, find the probability that the pointer lands on red (R) both spins.

Answer 1

The probability of the pointer lands on red(R) both spin = $\frac{1}{36}$

Step-by-step explanation:

Given,

The number of parts = 6

The pointer is spun twice.

To find the probability of the pointer lands on red(R) both spin.

Formula

Probability of an event = number of required outcomes ÷ the total number of outcomes.

P(A and B) = P(A)×P(B)

Now,

For one spin,

A = RED comes.

For second spin,

B = RED comes

So,

P(A) = $\frac{1}{6}$ and P(B) =  $\frac{1}{6}$

Then,

P(A and B) =  $\frac{1}{6}$ × $\frac{1}{6}$  = $\frac{1}{36}$

Hence, the probability of the pointer lands on red(R) both spin = $\frac{1}{36}$