Brad measured the length of an object as 2.1 * 10^4 cm. Which items might he have measured? Check all that apply.
2 answers:
Answer with explanation:
Length of an object
cm
Other unit of measurement are Meter and Kilometer.
→1 Meter = 100 cm
→1 Kilometer= 1,000 meter=100,000 cm
→→21,000 cm = 210 meter = 0.21 Km
Option B:→ length of a city park, is most suitable measurement ,among all other measurement ,that Brad has done.
Second option Might be: Option A→ Length of a city block , may be That Brad has measured.
All other options are Inappropriate, as they require smaller scale or may be larger Scale ,that brad has used to measure
1.≡ Height of a person →→→240 cm (Maximum of 8 feet)
2. ≡Distance across a city →→→1 Km or 2 Km or 3 Km...
3. ≡Height of an apple tree→→→1,000 cm (Maximum)
4. ≡Width of a screen in a theater→→→2,100 cm (Maximum)
5 ≡depth of water in a swimming pool→→→225 cm
None of the five things described above appears, that brad has measured.
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Answer:
The claim that all ages have purchase rates proportional to their driving rates is false.
Step-by-step explanation:
The complete question is:
A random sample of 160 car accidents are selected and categorized by the age of the driver determined to be at fault. The results are listed below. The age distribution of drivers for the given categories is 18% for the under 26 group, 39% for the 26-45 group, 31% for the 45-65 group, and 12% for the group over 65. Calculate the chi-square test statistic used to test the claim that all ages have crash rates proportional to their driving rates.
Age >26 26-45 46-65 45<
Drivers 66 39 25 30
A) 95.431
B)101.324
C)85.123
D)75.101
Solution:
In this case we need to test whether there is sufficient evidence to warrant rejection of the claim that all ages have crash rates proportional to their driving rates.
A Chi-square test for goodness of fit will be used in this case.
The hypothesis can be defined as:
<em>H₀</em>: The observed frequencies are same as the expected frequencies.
<em>Hₐ</em>: The observed frequencies are not same as the expected frequencies.
The test statistic is given as follows:
The values are computed in the table.
The test statistic value is 75.10.
The degrees of freedom of the test is:
n - 1 = 4 - 1 = 3
Compute the p-value of the test as follows:
p-value < 0.00001
*Use a Chi-square table.
p-value < 0.00001 < α = 0.05.
So, the null hypothesis will be rejected at any significance level.
Thus, there is sufficient evidence to warrant rejection of the claim that ages have crash rates proportional to their driving rates.
The equation to find the air pressure (P(h)) at a height above sea level (h) is given by
Where,
- P(h) is the new pressure at height h
is the air pressure at sea level, and
- h is the height (measured in meters).
We want to know the new pressure that is 65% of . So we should substitute
in P(h) (new pressure) to get the equation:
. Answer choice B is the correct one.
ANSWER: B
Benchmark are numbers that are used as standards to which the rest of the data is compared to. When counting numbers using a number line, the benchmark numbers are the intervals written on the axis. For benchmark numbers of 10, the number line on top of the attached picture is shown. Starting from 170, the tick marks are added by 10, such that the next numbers are 180, 190, 200, and so on and so forth. When you want to find 410, just find the benchmark number 410.
The same applies to benchmark numbers in intervals of 100. If you want to find 170, used the benchmark numbers 100 and 200. Then, you estimate at which point represents 170. For 410, you base on the benchmark numbers 400 and 500.
The same applies to benchmark numbers in intervals of 100. If you want to find 170, used the benchmark numbers 100 and 200. Then, you estimate at which point represents 170. For 410, you base on the benchmark numbers 400 and 500.