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natita [175]
2 years ago
5

Dakarai wrote the system of linear equations below. 7x+8y=28 and -3x+9y=-24 Dakarai then wrote the coefficient Matrix that repre

sented this system. Which Matrix could she have written?
7 8
-3 9

7 -3
8 9

7 8 28
-3 9 -24

7 -3 28
8 9 -24
Mathematics
1 answer:
DIA [1.3K]2 years ago
4 0

The system of linear equations a_1x+b_1y=c_1\\a_2x+b_2y=c_2

can be represented in the form of the Matrix as AX=B

Where A=\begin{pmatrix} a_1 &b_1 \\a_2   &b_2  \end{pmatrix}\\X=\begin{pmatrix} x\\y \\\end{pmatrix}\\ B=\begin{pmatrix} c_1\\c_2 \\\end{pmatrix}

The matrix A is called the coefficient matrix of the system of linear equations.

Here the given system of linear equation as:

7x+8y=28 \\ -3x+9y=-24

The matrix form of the given system of equation as

A=\begin{pmatrix} 7 &8 \\-3   &9  \end{pmatrix}\\B=\begin{pmatrix} 28\\-24 \\\end{pmatrix}\\X=\begin{pmatrix} x\\y \\\end{pmatrix}

The coefficient matrix of A is A=\begin{pmatrix} 7 &8 \\-3   &9  \end{pmatrix}

You might be interested in
Select the two statements that are true about the equation y−56=4(x+5)y-56=4(x+5).
Sergio [31]

The correct answers are:

The slope of the line is 4.

A point on the line is (−5, 56)

Step-by-step explanation:

Given equation is:

y-56=4(x+5)

The slope-intercept form is:

y-y_1=m(x-x_1)

Comparing both equations we get

m = 4

y-56=y-y_1\\y_1 = 56\\x+5 = x-x_1\\x_1=-5

The point is (-5,56)

So, the correct answers are:

The slope of the line is 4.

A point on the line is (−5, 56)

Keywords: Point-slope form, Slope

Learn more about point-slope form at:

  • brainly.com/question/2048256
  • brainly.com/question/2115122

#LearnwithBrainly

6 0
2 years ago
In a normally distributed data set a mean of 55 where 95% of the data fall between 47.4 and 62.6, what would be the standard dev
tresset_1 [31]

Answer:

The standard deviation of that data set is 3.8

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 55

95% of the data fall between 47.4 and 62.6. This means that 47.4 is 2 standard deviations below the mean and 62.6 is two standard deviations above the mean.

Using one of these points.

55 + 2sd = 62.6

2sd = 7.6

sd = 7.6/2

sd = 3.8

The standard deviation of that data set is 3.8

6 0
2 years ago
Two numbers are randomly selected on a number line numbered from 1 to 9. Match each scenario to its probability.
Talja [164]

Answer:

1/9; 4/9; 1/12; 1/6

Step-by-step explanation:

the probability that both numbers are greater than 6 if the same number can be chosen twice--> 3/9 * 3/9 = 1/9

the probability that both numbers are less than 7 if the same number can be chosen twice --> 6/9 * 6/9 = 4/9

the probability that both numbers are odd numbers less than 6 if the same numbers cannot be chosen twice --> 3/9 * 2/8 = 1/12

the probability that both numbers are even numbers if the same numbers cannot be chosen twice --> 4/9 * 3/8 = 1/6

5 0
2 years ago
Read 2 more answers
In ΔABC, AD and BE are the angle bisectors of ∠A and ∠B and DE ║ AB . If m∠ADE is with 34° smaller than m∠CAB, find the measures
Charra [1.4K]

Answer:

34°

Step-by-step explanation:

If m∠ADE is with 34° smaller than m∠CAB, then denote

m∠ADE=x°,

m∠CAB=(x+34)°.

Since  DE ║ AB, then

m∠ADE=m∠DAB=x°.

AD is angle A bisector, then

m∠EAD=m∠DAB=x°.

Thus,

m∠CAB=m∠CAD+m∠DAB=(x+x)°=2x°.

On the other hand,

m∠CAB=(x+34)°,

then

2x°=(x+34)°,

m∠ADE=x°=34°.

7 0
2 years ago
The newest invention of the 6.431x staff is a three-sided die. On any roll of this die, the result is 1 with probability 1/2, 2
Gwar [14]

Answer:

<h2>The answer is 0.23(approx).</h2>

Step-by-step explanation:

The given die is a three sided die, hence, there are only three possibilities of getting the outcomes.

We need to find the probability of getting exactly 3s as the result.

From the sequence of 6 independent rolls, 2 rolls can be chosen in ^6C_2 = \frac{6!}{2!\times4!} = \frac{30}{2} = 15 ways.

The probability of getting two 3 as outcome is \frac{1}{4} \times\frac{1}{4} = \frac{1}{16}.

In the rest of the 4 sequences, will not be any 3 as outcome.

Probability of not getting a outcome rather than 3 is 1 - \frac{1}{4} = \frac{3}{4}.

Hence, the required probability is 15\times\frac{1}{16}(\frac{3}{4})^4 = \frac{1215}{4096}≅0.2966 or, 0.23.

4 0
2 years ago
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