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2 years ago

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If SYSTEM is coded as '131625', and KARMA is coded as '94854' then MARKET is coded as _____? (A) 845926 (B) 548926 (C) 629845 (D

) 548629

1 answer:

MArishka [77]2 years ago

5 0

Answer:

B. 548926

Step-by-step explanation:

Given

SYSTEM => '131625', and KARMA => '94854'

Required

MARKET is coded as?

To solve this, we simply map out each letter to the given characters;

This is done as follows:

S-> 1

Y-> 3

S-> 1

T-> 6

E -> 2

M-> 5

K-> 9

A-> 4

R-> 8

M-> 5

A -> 4

Remove repetitions

S-> 1

Y-> 3

T-> 6

E -> 2

M-> 5

K-> 9

R-> 8

A -> 4

Now, we can code MARKET using the same system

M-> 5

A -> 4

R-> 8

K-> 9

E -> 2

T-> 6

MARKET => 548926

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Read 2 more answers

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Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

<em>First case</em>

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\B=30^o$

Applying the law of sines

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(A)}=\frac{2}{sin(30^o)}$

$sin(A)=1$

so

$A=90^o$

Find the measure of angle C

In a right triangle

we know that

$B+C=90^o$ ----> by complementary angles

$B=30^o$

therefore

$C=60^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}$

$c=2\sqrt{3}\ units$

therefore

The dimensions of the triangle are

$A=90^o$

$B=30^o$

$C=60^o$

$a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units$

<em>Second case</em>

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\A=30^o$

Applying the law of sines

Find the measure of angle B

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(30^o)}=\frac{2}{sin(B)}$

$sin(B)=0.25$

so

using a calculator

$B=14.48^o$

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

$A+B+C=180^o$

$A=30^o\\B=14.48^o$

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Applying the law of sines

$\frac{c}{sin(C)}=\frac{a}{sin(A)}$

substitute the given values

$\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}$

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therefore

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$B=14.48^o$

$C=135.52^o$

$a=4\ units\\b=2\ units\\c=5.61\ units$

see the attached figure to better understand the problem

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2 years ago