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vesna_86 [32]
2 years ago
14

Evaluate the expression x²-3y +12 for x= -2 and y = 5​

Mathematics
1 answer:
n200080 [17]2 years ago
4 0

Answer:

1

Step-by-step explanation:

  • x²-3y + 12
  • (-2)²-3(5) + 12
  • 4 - 15 + 12
  • -11 + 12
  • 1
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Suppose that you want to mix two coffees in order to obtain 100 pounds of a blend. If x represents the number of pounds of coffe
Svetach [21]

Answer: 100-x

Therefore, the algebraic exp

Step-by-step explanation:

Given : x represents the number of pounds of coffee​ A.

The total weight of the mix of coffee A and coffee B = 100 pounds.

Then , we have the following expression to represents the number of pounds of coffee B:-

100-x

Therefore, the algebraic expression that represents the number of pounds of coffee B. :-

100-x

5 0
2 years ago
Which hyperbola has one focus point in common with the hyperbola (y+11)^2/(15^2)-(x-7)^2/(8^2)=1
irina [24]
\bf \textit{hyperbolas, vertical traverse axis }\\\\
\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center\ ({{ h}},{{ k}})\\
vertices\ ({{ h}}, {{ k}}\pm a)
\end{cases}\\\\
-------------------------------\\\\
\cfrac{(y+11)^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\implies \cfrac{(y-(-11))^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\\\\
-------------------------------\\\\
c=\textit{distance from the center to either foci}\\\\
c=\sqrt{a^2+b^2}\implies c=\sqrt{15^2+8^2}\implies \boxed{c=17}

now, if you notice, the positive fraction, is the one with the "y" variable, and that simply means, the hyperbola traverse axis is over the y-axis, so it more or less looks like the picture below.

now, from the hyperbola form, we can see the center is at (7, -11), and that the "c" distance is 17.

so, from -11 over the y-axis, we move Up and Down 17 units to get the foci, which will put them at (7, -11-17) or (7, -28) and (7 , -11+17) or (7, 6)

5 0
2 years ago
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Rory is staying in a cabin on a hill 300 feet above sea level. She walks down the hill to the water’s edge. The equation of her
Anastasy [175]

For this problem, we plug in the <em>numbers for t</em> and the <em>appropriate letters for e</em> to the equation <em>e = 300 - 10t</em>.

a) a = 300 - 10(-2)

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simplify: a = 320 ft.

But, this is not a viable point because when t≤0, she doesn't move anywhere, thus, should consistently be 300 ft.

b) b = 300 - 10(3.5)

simplify: b = 300 - 35

simplify: b = 265 ft.

c) c = 300 - 10(30)

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simplify: c = 0 ft.

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What is the range of the function y = 2 e Superscript x Baseline minus 1
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Answer:

I may be able to help you I need a image though

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Round to the nearest ten thousand 905154
kolbaska11 [484]
You want to round 905,154 to the nearest ten-thousands place. The ten-thousands place in your number is shown by the bold underlined digit here:

9<em><u>0</u></em>5,154

    To round 905,154 to the nearest ten-thousands place...

    The digit in the ten-thousands place in your number is the 0. To begin the rounding, look at the digit one place to the right of the 0, or the 5, which is in the thousands place.

    Since the 5 is greater than or equal to 5, we'll round our number up by

        Adding 1 to the 0 in the ten-thousands place, making it a 1.

    and by changing all digits to the right of this new 1 into zeros.

The result is: 910,000.

So, 905,154 rounded to the ten-thousands place is 910,000.

5 0
2 years ago
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