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Hatshy [7]
2 years ago
5

The amounts of vitamin C (in milligrams) for 100g (3.57 ounces) of various randomly selected fruits and vegetables are listed. I

s there sufficient evidence to conclude that the standard deviation differs from 12 mg? Use alpha = 0.10. Use a graphing calculator with the program SDHYP and the P-value method. Source: Time Almanac 2012. State the hypotheses and identify the claim with the correct hypothesis. H_0: sigma H_1: sigma This hypothesis test is a (select) test.
Mathematics
1 answer:
34kurt2 years ago
4 0

Answer:

H0: sigma=12

H1:sigma≠12

This hypothesis test is a two tailed test.

Step-by-step explanation:

The null value described in the statement is 12 mg. So, the null hypothesis would be sigma=12. As the statement states that whether there is sufficient evidence to conclude that standard deviation differs from 12 mg, so the alternative hypothesis would be sigma ≠12. The alternative hypothesis contains inequality sign so, the hypothesis test is a two tailed test.

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Printed circuit cards are placed in a functional test after being populated with semiconductor chips. A lot contains 140 cards,
hjlf

Answer:

a) 0.9644 or 96.44%

b) 0.5429 or 54.29%

Step-by-step explanation:

a) The probability that at least 1 defective card is in the sample P(A) = 1 - probability that no defective card is in the sample P(N)

P(A) = 1 - P(N) .....1

Given;

Total number of cards = 140

Number selected = 20

Total number of defective cards = 20

Total number of non defective cards = 140-20 = 120

P(N) = Number of possible selections of 20 non defective cards ÷ Number of possible selections of 20 cards from all the cards.

P(N) = 120C20/140C20 = 0.0356

From equation 1

P(A) = 1 - 0.0356

P(A) = 0.9644 or 96.44%

b) Using the same method as a) above

P(A) = 1 - P(N) .....1

Given;

Total number of cards = 140

Number selected = 20

Total number of defective cards = 5

Total number of non defective cards = 140-5 = 135

P(N) = 135C20/140C20 = 0.457

From equation 1

P(A) = 1 - 0.4571

P(A) = 0.5429 or 54.29%

8 0
2 years ago
What additional information could you use to show that ΔSTU ≅ ΔVTU using SAS? Check all that apply.
Ugo [173]
I believe the correct answers are:

<span>UV = 14 ft and m∠TUV = 45°</span>
<span>ST = 20 ft, UV = 14 ft, and m∠UST = 98°

Or, in other words, Options A and D.
</span>
6 0
2 years ago
Read 2 more answers
A website charges $3 for each movie you download. They also charge a one-time sign-up fee of $14.99. whats the input variable?
natka813 [3]
Y= 3x + 14.99
'x' is the input variable
5 0
2 years ago
Read 2 more answers
A bridge is rated to a capacity of 100 British tons. What is the maximum weight the bridge can support in kilograms? (Round to t
S_A_V [24]

Maximum weight the bridge can support in kilograms is 101696

Step-by-step explanation:

  • Step 1: Given capacity of bridge = 100 British tons. Find how many kilograms are equivalent to 1 British ton.

1 British ton = 2240 pounds

1 pound = 0.454 kg

⇒ 1 British ton = 2240 × 0.454 kg = 1016.96 kg

  • Step 2: Find how many kilograms are in 100 British tons.

⇒ 100 × 1016.96 = 101696

3 0
2 years ago
There were 8 judges at a gymnastics competition. Kathleen received these scores for her performance on the uneven parallel bars.
Korolek [52]

Answer:

below

Step-by-step explanation:

mean : 8.8

The mean is the average, so you find it by adding all the numbers together and dividing by n, or how many numbers there are. For this, I added to get 70.4 and divided that by 8 (8 total scores).

70.4/8 = 8.8.

median : 8.85

The median is the middle of the data set, so you put the numbers in increasing order (lowest number to highest number) and then finding the middle of that set. For this set, since there is an even number of numbers (8), you have to find the middle by adding the two middle numbers and dividing by 2.

8.2, 8.7, 8.8, 8.8, 8.9, 8.9, 8.9, 9.2

The middle numbers are 8.8 and 8.9, so you add those together and divide by 2 to get 8.85.  

mode : 8.9

The mode is just what number appears most often. Because 8.9 appears three times in this data set, more than any other number, the mode is 8.9.

b. The mean reflects a typical score because it is the average, and is used most often when someone is expressing a typical or "average" score. It is the score most people are likely to get, and as there are no outliers in this data set, it reflects a typical score for this data set. It is also the same as the mode, or most often score, in this data set.

6 0
2 years ago
Read 2 more answers
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