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2 years ago

What did you do to find the GCF given the remaining factors?

Mathematics

1 answer:

scoray [572]2 years ago

8 0

Answer:

To find GCD or HCF, just write the common factor.

Step-by-step explanation:

To find the GCF of greater numbers, you can factor each number to find their prime factors, identify the prime factors they have in common, and then multiply those together.

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The 3rd degree Taylor polynomial for cos(x) centered at a = π 2 is given by, cos(x) = − (x − π/2) + 1/6 (x − π/2)3 + R3(x). Usin

Otrada [13]

Answer:

The cosine of 86º is approximately 0.06976.

Step-by-step explanation:

The third degree Taylor polynomial for the cosine function centered at $a = \frac{\pi}{2}$ is:

$\cos x \approx -\left(x-\frac{\pi}{2} \right)+\frac{1}{6}\cdot \left(x-\frac{\pi}{2} \right)^{3}$

The value of 86º in radians is:

$86^{\circ} = \frac{86^{\circ}}{180^{\circ}}\times \pi$

$86^{\circ} = \frac{43}{90}\pi\,rad$

Then, the cosine of 86º is:

$\cos 86^{\circ} \approx -\left(\frac{43}{90}\pi-\frac{\pi}{2}\right)+\frac{1}{6}\cdot \left(\frac{43}{90}\pi-\frac{\pi}{2}\right)^{3}$

$\cos 86^{\circ} \approx 0.06976$

The cosine of 86º is approximately 0.06976.

8 0

2 years ago

The average of Johnny’s two tests is a 92. What must he get on a 3rd test to raise his average to a 94?

zheka24 [161]

Reread, take time, and concentrate

5 0

2 years ago

Read 2 more answers

Compare the functions shown below: f(x) = 4x + 5 g(x) tangent function with y intercept at 0, 2 h(x) = 3 sin(2x + π) − 2 Which f

KATRIN_1 [288]

The y-intercept of the graph of a function is the value of f(0) for any function f.
That is, it is the y-value in the pair (0, y)

The y-intercept of <span>f(x) = 4x + 5 is f(0)=4*0+5=5

The y-intercept of (0, 2) is 2.

The y-intercept of </span>h(x) = 3 sin(2x + π) − 2 is:

h(0) = 3 sin(2*0 + π) − 2=3 sin(π) − 2=3*0-2=-2

<span>Answer: The function f has the greatest y-intercept.

</span>

7 0

2 years ago

The solutions to the linear differential equation d2u/dt2 = u form a vector space (since combinations of solutions are still sol

maw [93]

Serious high school. This is one of the few differential equations I can solve.

The usual particular solution is $u=e^t$ because $e^t$ is its own derivative.

An independent solution is $u=e^{-t}$ which has a negative sign in the first derivative which turns back to positive in the second.

The arbitrary linear combination spans the solution space:

$u= c_1 e^t + c_2 e^{-t}$

But we only are asked for the basis.

Answer: $\textrm{. } \quad e^t, \quad e^{-t}$

5 0

2 years ago

Two students, Claude and Diane, were asked to use synthetic division and the Remainder Theorem to find the value of f(2) given f

ad-work [718]

Answer:

Step-by-step explanation:

Part A

In applying the synthetic division, the polynomial would be fully expressed as

2x³ + 0x² + 5x - 6

The coefficients are 2, 0, 5 and - 6

The working becomes

2| 2 0 5 -6

4 8 16

2 4 13 10

The student that correctly used synthetic division to find f(2) is Claudia

Part B

The value of f(2) is

2(2)^3+5(2) - 6

= (2 × 8) + 10 - 6

= 16 + 10 - 6 = 20

Part C

x - 2 is not a factor of 2x³ + 5x - 6 because there is a remainder of 20.

Part D

The methods that can be used to find out if x - 2 is a factor of 2x³ + 5x - 6 are synthetic division, long division, remainder theorem

8 0

2 years ago

What did you do to find the GCF given the remaining factors?​

What did you do to find the GCF given the remaining factors?