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mr Goodwill [35]
2 years ago
11

Simplify. A) 4√3 + 6 B) 6√3 + 4 C) 6√6 + 3

Mathematics
1 answer:
Nadusha1986 [10]2 years ago
3 0
\frac{ 8\sqrt{6mn} + 6\sqrt{8mn} }{ 2\sqrt{2mn}}

First, break it up into two fractions:

\frac{ 8\sqrt{6mn} + 6\sqrt{8mn} }{ 2\sqrt{2mn}} = \frac{8\sqrt{6mn}}{ 2\sqrt{2mn}} + \frac{6\sqrt{8mn}}{ 2\sqrt{2mn}}

Next, you can simplify the numbers outside of the square root:

\frac{8\sqrt{6mn}}{ 2\sqrt{2mn}} + \frac{6\sqrt{8mn}}{ 2\sqrt{2mn}} = \frac{4\sqrt{6mn}}{\sqrt{2mn}} + \frac{3\sqrt{8mn}}{\sqrt{2mn}}

Since the values are being acted by the same function, being under a radical, you can simplify these too:

\frac{4\sqrt{6mn}}{\sqrt{2mn}} + \frac{3\sqrt{8mn}}{\sqrt{2mn}} = {4\sqrt{3}} + {3\sqrt{4}}

Finally, the square root of 4 is 2, so it would be expressed like this:

{4\sqrt{3}} + {3\sqrt{4}} = {4\sqrt{3}} + {3(2) = {4\sqrt{3}} + 6

Your answer should be A.
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We have been given that Darren invests $4,500 into an account that earns 5% annual interests. We are asked to find the amount in his account after 10 years, if the interest rate is compounded annually, quarterly, monthly, or daily.

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A=P(1+\frac{r}{n})^{nt}, where,

A = Final amount,

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t = Time in years.

5\%=\frac{5}{100}=0.05  

When compounded annually, n=1:

A=4500(1+\frac{0.05}{1})^{1\cdot 10}

A=4500(1.05)^{10}

A=4500(1.6288946267774414)

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When compounded quarterly, n=4:

A=4500(1+\frac{0.05}{4})^{4\cdot 10}

A=4500(1.0125)^{40}

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When compounded monthly, n=12:

A=4500(1+\frac{0.05}{12})^{12\cdot 10}

A=4500(1.00416666)^{120}

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When compounded daily, n=365:

A=4500(1+\frac{0.05}{365})^{365\cdot 10}

A=4500(1.0001369863013699)^{3650}

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A=7418.9916619456\approx 7419.00

Since amount earned will be maximum, when interest is compounded daily, therefore, Darren should use compounded daily interest rate.

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