1. x= 11.7 μ = 7
2. z11.7= 1.3
3. Is 11.7 within a z-score of 3?
a. Yes because z11.7 < 3.
4. Which statement is true of z11.7?
b. z11.7 is between 1 and 2 standard deviations of the mean.
Answer:
There's two ways to solve this.
Step-by-step explanation:
First way:
Let's divide the width and length by 2.3.
46÷2.3=20
69÷2.3=30
20×30
600 ft²
Second Way:
Let's find the area of the actual room.
46×69
3,174 ft²
Let's find the scale drawing squared.
2.3²=5.29
3,174÷5.29
600 ft²
Answer:
< CFE = 40°
Step-by-step explanation:
To better understand the solution, see attachment for the diagram.
Given:
BC parallel to DE
Measure of Arc BD = 58°
Measure of Arc DE = 142°
First step: Draw a diameter that passes through the centre of the circle and name it. In this case, the diameter is line ST.
The line ST divides the arc BD and arc DE into half.
That is:
Arc SC = 1/2(arc BC) =1/2(58)
Arc SC = 29°
Arc TE = 1/2(arc DE) =1/2(142)
Arc TE = 71°
Arc SC + Arc CE + Arc TE = 180° (Sum of angles in a semicircle
29° + Arc CE + 71° = 180°
Arc CE + 100° = 180°
Arc CE = 180-100
Arc CE = 80°
Inscribed angle = 1/2(intercepted angle)
<CFE = 1/2(Arc CE )
<CFE = 1/2(80)
< CFE = 40°
Answer:
a. 12
b. 7.200 and 2.683
Step-by-step explanation:
The computation is shown below:
Given that
P = 0.40 and n = 30
a)
The expected value of received e-mails is
= n × p
= 30 × 0.4
= 12
b)
The variance of emails received is
= n × p × (1 - p)
= 30 × 0.4 × 0.6
= 7.200
Now
The standard deviation of emails received is
= sqrt(variance)
= 2.683
We simply applied the above formula