Start with 90/240, then reduce the fraction
you can reduce by dividing each by 10 to get 9/24
reduce more from there, seeing that each number can be divided by 3
9/3 = 3
24/3 = 8
answer 3/8
Answer:
Given:
length of the wire = 0.20 meters
magnetic field strength = 0.45 newtons/amperes meter
speed = 10.0 meters per second
emf = B * l * v
B = flux density ; l = length of the wire ; v = velocity of the conductor
emf = 0.45 newtons / ampere meter * 0.20 meters * 10.0 meters/seconds
emf = 0.90 volts
The emf produced is 0.90 volts.
Step-by-step explanation:
Answer: the correct answer is D.
Step-by-step explanation:
Answer:
1.79553
Step-by-step explanation:
Step 1: Write expression
log₁₀(√(69.5² - 30.5²))
Step 2: Evaluate square root
log(√(4830.25 - 930.25))
log(√3900)
log(62.45)
Step 3: Find log
log₁₀ (or log)
log(62.45) = 1.79553
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To use the table method. we find values that are easily evaluated by log₁₀
log₁₀(10) = 1
log₁₀(50) = 1.69897
log₁₀(100) = 2
So we know that log₁₀(62.45) is between 1 and 2 and greater that 1.69897.
Let stadium 1 be the one on the left and stadium 2 the one on the right.
Angle above stadium 1 is 72.9° and the angle above stadium 2 is 34.1° using the angle property of alternate angles(because both the ground and the dotted line are parallel).
For the next part we need to use the trigonometric function of tangent.
As tan x = opposite / adjacent,
Tan 72.9°=1500/ adjacent ( the ground from O to stadium 1)
Therefore the adjacent is 1500/tan 72.9°= 461.46 m( to 5 s.f.)
Same for the next angle,
Tan 34.1°=1500/ adjacent ( the ground from O to stadium 2)
Therefore, the adjacent is 1500/tan 34.1° = 2215.49 m (to 5 s.f.)
Thus, the distance between both stadiums is 2215.49-461.46= 1754.03 m
Correcting the answer to whole number gives you 1754 m which is the option C.
