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antiseptic1488 [7]
2 years ago
12

Darren invests $4,500 into an account that earns 5% annual interests. How much will be in the account after 10 years if the inte

rest rate is compounded annually, quarterly, monthly, or daily? Which compounded interest rate should Darren choose?
Mathematics
1 answer:
xz_007 [3.2K]2 years ago
4 0

We have been given that Darren invests $4,500 into an account that earns 5% annual interests. We are asked to find the amount in his account after 10 years, if the interest rate is compounded annually, quarterly, monthly, or daily.

We will use compound interest formula to solve our given problem.  

A=P(1+\frac{r}{n})^{nt}, where,

A = Final amount,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

5\%=\frac{5}{100}=0.05  

When compounded annually, n=1:

A=4500(1+\frac{0.05}{1})^{1\cdot 10}

A=4500(1.05)^{10}

A=4500(1.6288946267774414)

A=7330.025820498\approx 7330.03

When compounded quarterly, n=4:

A=4500(1+\frac{0.05}{4})^{4\cdot 10}

A=4500(1.0125)^{40}

A=4500(1.6436194634870132)

A=7396.28758569\approx 7396.29

When compounded monthly, n=12:

A=4500(1+\frac{0.05}{12})^{12\cdot 10}

A=4500(1.00416666)^{120}

A=4500(1.64700949769)

A=7411.542739605\approx 7411.54

When compounded daily, n=365:

A=4500(1+\frac{0.05}{365})^{365\cdot 10}

A=4500(1.0001369863013699)^{3650}

A=4500(1.6486648137656943695)

A=7418.9916619456\approx 7419.00

Since amount earned will be maximum, when interest is compounded daily, therefore, Darren should use compounded daily interest rate.

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lbvjy [14]
Answer:
slope of the line is -0.5
y-intercept is 13

Explanation:
The general formula of the linear equation is:
y = mx + c 
where m is the slope and c is the y-intercept

1- getting the slope:
We are given the two points:
(6,10) representing (x1 , y1)
(12,7) representing (x2 , y2)
The slope of the line will be calculated as follows:
m = (y2-y1) / (x2-x1) = (7-10) / (12-6) = -3/6 = -0.5
The equation of the line now becomes:
y = -0.5x + c

2- getting the value of the y-intercept:
To get the value of the y-intercept (c), we will use any of the given points, substitute in the equation of the line and solve for c. I will use the point (6,10) as follows:
y = -0.5x + c
10 = -0.5(6) + c
10 = -3 + c
c = 13

Based on the above, the equation of the line would be:
y = -0.5x + 13

Hope this helps :)
8 0
1 year ago
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What is the concentration of a new solution obtained by mixing 25ml of water with 125ml of a 20% salt solution in water?
expeople1 [14]
Given that the concentration of salt in a 125 ml of salt solution is 20%, this means that the ratio of salt to water in the solution is 20 : 80 = 1 : 4.

Thus, the amount of salt in the 125 ml 20% salt solution is given by 20% of 125 = 0.2 x 125 = 25ml and the amount of water in the 125ml 20% salt solution is 125 - 25 = 100 ml.

When 25 ml of water is added to the 125 ml 20% salt solution, the new amount of water is 100 + 25 =125 and the amount of salt remain 25 ml.

Thus, the new volume of the solution is 125 + 25 = 150 ml and the proprtion of salt in the new solution is given by 25 / 150 = 0.1667

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2 years ago
A wedding website states that the average cost of a wedding is $25,809. One concerned bride hopes that the average is less than
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Answer:

1)

Null hypothesis            H₀ : μ = 25,809

Alternative hypothesis H₁ : μ < 25,809

2) Test Statistic = -1.44

3) Conclusion:

The result is significant, there is sufficient evidence to support the bride’s hope at the 0.10 level of significance.

Step-by-step explanation:

Given the data in the question;

Sample mean x" = 24,638

sample size n = 46

standard deviation σ = 5531

level of significance ∝ = 0.10

NULL and ALTERNATIVE HYPOTHESIS

Null hypothesis            H₀ : μ = 25,809

Alternative hypothesis H₁ : μ < 25,809

TEST STATISTICS

Z = (x"-μ) / σ√n

we substitute

Z = (24,638 - 25,809) / (5531/√46)

Z = -1171 / 815.5

Z = -1.44

Test Statistic = -1.44

Now, from normal z-table;

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P-value = 0.0749

Since P-value ( 0.0749 ) is less than level of significance ( 0.10 ), we reject H₀.

Conclusion:

The result is significant, there is sufficient evidence to support the bride’s hope at the 0.10 level of significance.

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