No of games lost = 84 - 14 = 70
No of games played = 84 + 70 = 154
Using the normal distribution, it is found that z is Z = 1.26, given by option B.
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Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X, which is also the <u>area under the normal curve to the left of Z</u>. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X, which is also the <u>area under the normal curve to the right of Z</u>.
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- Area under the normal curve between 0 and the z-value is 0.3962.
- Z = 0 has a p-value of 0.5.
- Thus, we need to find z with a p-value of 0.5 + 0.3962 = 0.8962.
- Looking at the z-table, this is Z = 1.26, given by option B.
A similar problem is given at brainly.com/question/22940416
Answer:
The value of the computer is given by
.
Step-by-step explanation:
A computer sells for $900.
If the price of the computer loses 30% of its value per year, then it is compounded every year.
Now, the price of the computer t years after it is sold will be
........... (1)
Therefore, the value of the computer is given by the above equation (1). (Answer)
Answer:
derivative of the vector function given = ( -16-22t, 14-36t, -2-16t )
Step-by-step explanation:
given data:
vector function : r(t) = ta*(b+tc)
a = ( 2,-3.4) . b = (-4,5,-1). c = ( -2,-1,5)
to find the derivative of the vector function we will differentiate with respect to x attached below is the detailed solution
Answer:
dy/dx = -1/√(1 - x²)
For 0 < y < π
Step-by-step explanation:
Given the function cos y = x
-siny dy = dx
-siny dy/dx = 1
dy/dx = -1/siny (equation 1)
But cos²y + sin²y = 1
=> sin²y = 1 - cos²y
=> siny = √(1 - cos²y) (equation 2)
Again, we know that
cosy = x
=> cos²y = x² (equation 3)
Using (equation 3) in (equation 2), we have
siny = √(1 - x²) (equation 4)
Finally, using (equation 4) in (equation 1), we have
dy/dx = -1/√(1 - x²)
The largest interval is when
√(1 - x²) = 0
=> 1 - x² = 0
=> x² = 1
=> x = ±1
So, the interval is
-1 < x < 1
arccos(1) < y < arxcos(-1)
= 0 < y < π