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Blizzard [7]
2 years ago
9

Cindy found a collection of baseball cards in her attic worth $8,000. the collection is estimated to increase in value by 1.5% p

er year. write an exponential growth function and find the value of the collection after 7 years
Mathematics
1 answer:
Sergio [31]2 years ago
7 0
A]
Exponential function is given by the form:
y=a(b)ˣ
where:
a=initial value
b=growth factor
From the question:
a=$8000, b=1.015, 
thus the exponential growth function of this situation is:
y=8000(1.015)ˣ

b] The value of the collection after 7 years will be:
x=7 years
Using the formula:
y=8000(1.015)ˣ
plugging the values we get:
y=8000(1.015)⁷
y=8,878.76

Answer: $8,878.76
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Show a way to count from 170 to 410 using tens and hundreds. circle at least 1 benchmark number
Anastasy [175]
Benchmark are numbers that are used as standards to which the rest of the data is compared to. When counting numbers using a number line, the benchmark numbers are the intervals written on the axis. For benchmark numbers of 10, the number line on top of the attached picture is shown. Starting from 170, the tick marks are added by 10, such that the next numbers are 180, 190, 200, and so on and so forth. When you want to find 410, just find the benchmark number 410.

The same applies to benchmark numbers in intervals of 100. If you want to find 170, used the benchmark numbers 100 and 200. Then, you estimate at which point represents 170. For 410, you base on the benchmark numbers 400 and 500.

6 0
1 year ago
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Computer keyboard failures are due to faulty electrical connects (12%) or mechanical defects (88%). Mechanical defects are relat
Margaret [11]

Answer:

a) 23.76%

b) 7.8%

Step-by-step explanation:

a) probability that a failure is due to loose keys.

loose key failure (27%) comes under mechanical failure(88%)

hence, probability that a failure is due to loose keys= 0.27×0.88= 0.2376= 23.76%

b)  probability that a failure is due to improperly connected wire which comes under electrical failure = 0.12×0.13

probability that a failure is due to poorly welded wires which comes under electrical failure= 0.52×0.12

now, the probability that a failure is due to improperly connected or poorly welded wires. = 0.12(0.52+0.13)= 0.078= 7.8%

6 0
1 year ago
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Angie's car is valued at $22,000, and she owes $20,000 on it. What is her<br><br> current equity?
amid [387]

Answer: 2,000

Step-by-step explanation: 22,000 - 20,000 = 2,000

Angie’s current equity on her car is 2,000

6 0
1 year ago
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In high-school 135 freshmen were interviewed.
timama [110]

Answer:

a) n(none) = 25

b) n(PE but not Bio) = 25

c) n(ENG but not both BIO and PE) = 55

d) n(students that did not take Eng or Bio) = 40

e) P( Students did not take exactly two subjects) = 0.65

Step-by-step explanation:

From the Venn diagram drawn:

a) Number of students that took none

n(Freshmen) = 135

n(all three) = 5

n (PE and Bio) = 10

n(PE and Eng) = 15

n(Bio and Eng) = 7

n (PE and Bio only) = 10 - 5 = 5

n(PE and Eng only) = 15 - 5 = 10

n(Bio and Eng only) = 7 - 5 = 2

n(PE only) = 35 - 5 - 5 - 10 = 15

n(Bio only) = 42 - 5 - 5 - 2 = 30

n(Eng only) = 60 - 10 - 5 -2 = 43

n(Freshmen) = n(PE only) + n(Bio only) + n(Eng only) + n(PE and Bio only) + n(PE and Eng only) + n(Bio and Eng only) + n(all three) + n(none)

135 = 15 + 30 + 43 + 5 + 10 + 2 + 5 + n(none)

135 = 110 + n(none)

n(none) = 135 - 110

n(none) = 25

b)Number of students that too PE but not Bio

n(PE but not bio)= n(PE only) + n(PE and Eng only)

n(PE but not Bio) = 15 + 10

n(PE but not Bio) = 25

c) Number of students that took ENG but not both BIO and PE

n(ENG but not both BIO and PE) = n(Eng only) + n(Eng and Bio only) + n(Eng and PE only) = 43 + 2 + 10

n(ENG but not both BIO and PE) = 55

d) Number of students that did not take ENG or BIO

n( students that did not take Eng or Bio) = n(PE only) + n(none)

n(students that did not take Eng or Bio) = 15 + 25

n(students that did not take Eng or Bio) = 40

e) Probability that a randomly-chosen student from this group did not take exactly two subjects

n( Students that did not take exactly two subjects) = n(PE only) + n(Bio only) + n(Eng only)

n( Students that did not take exactly two subjects) = 15 + 30 + 43

n( Students that did not take exactly two subjects) = 88

P( Students did not take exactly two subjects) = 88/135

P( Students did not take exactly two subjects) = 0.65

3 0
1 year ago
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You have a set of numeric tiles, from 1 and 6. You randomly chose one tile. How many possible outcomes are there?
fredd [130]
The are 6 possible outcomes because there are 6 tiles.
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