Answer:
12 = f(40)
Step-by-step explanation:
From the given information:
We are being told that:
G = tons per week
p = people in thousands
However, the relation existing between the amount of garbage that is produced by a city with population p can be expressed as:
G = f(p)
Similarly, they said there exists a total population of 40000 persons in the town of Tola. i.e. 40 thousand and also 12 tons of garbage is produced by week i.e. that will be the value for G.
Then, we have:
12 = f(40)
<span>In the question "Harriet earns the same amount of money each day. Her gross pay at the end of 7 work days is 35h + 56 dollars. Which expression represents her gross pay each day"
To obtain the expression that represents her gross pay each day, we divide the given expression by 7 to get (35h + 56) / 7 = 35h / 7 + 56 / 7 = 5h + 8
Therefore, the expression that represents her gross pay each day is 5h + 8.</span>
Answer:
Longest possible length for each of the shorter lengths of ribbon is 9 cm because greatest common factor for both 36 and 45 is 9.
Step-by-step explanation:
Alannah has two ribbons one length is 36cm and other is 45cm.
It asked to find shorter length of ribbons that each cut into equal pieces with out no ribbon left over.
So, let's find greatest common factor for both 36 and 45.
Let's prime factor each number
36= 2*2*3*3
45= 3*3*5
So, GCF is product of common factors for both numbers.
GCF= 3*3 =9
So, longest possible length for each of the shorter lengths of ribbon is 9 cm.
Learn more about GCF in brainly.com/question/21612147.
The question is incomplete. Here is the complete question:
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.
Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?
Answer:
40.13%
Step-by-step explanation:
Let 'A' be the event of not missing a target in 10 attempts.
Therefore, the complement of event 'A' is 
Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.
Now, 
We know that the sum of probability of an event and its complement is 1.
So, 
Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.