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2 years ago

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Triangle J K L is shown. Point N is the midpoint of side J L and point M is the midpoint of side K L. The length of J K is 19.6

meters. The lengths of J N and N L are 7.4 meters. The lengths of K M and M L are 10.7 meters. What is the distance between points M and N?

2 answers:

OlgaM077 [116]2 years ago

6 0

Answer:

Its 9.8

Step-by-step explanation:

I did it on Edge! : )

EastWind [94]2 years ago

4 0

Answer:

i think 9.8 but im not sure

Step-by-step explanation:

You might be interested in

The annual salaries of all employees at a financial company are normally distributed with a mean of $34,000 and a standard devia

Alla [95]

Answer:

$z=5$

Step-by-step explanation:

We have been given that the The annual salaries of all employees at a financial company are normally distributed with a mean of $34,000 and a standard deviation of $4,000.

To solve our given problem we will use z-score formula.

$z=\frac{x-\mu}{\sigma}$ where,

$z=\text{z-score}$ ,

$x=\text{Sample score}$ ,

$\mu=\text{Mean}$ ,

$\sigma=\text{Standard deviation}$

Upon substituting our given values in z-score formula we will get,

$z=\frac{54,000-34,000}{4,000}$

$z=\frac{20,000}{4000}$

$z=5$

Therefore, the z-score of a company employee who makes an annual salary of $54,000 is 5.

4 0

2 years ago

Read 2 more answers

Conscientiousness is a tendency to show self-discipline, act dutifully, and aim for achievement. The trait shows a preference fo

MAVERICK [17]

Answer:

a

The Null hypothesis represented as

$H_0: \mu_1 - \mu_2 = 0$

The Alternative hypothesis represented as

$H_a: \mu_1 - \mu_2 < 0$

b

p-value = P(Z < -3.37 ) = 0.000376

c

There is insufficient evidence to conclude that graduate students score higher, on average, on the HPI than undergraduate students

Step-by-step explanation:

From the question we are told that

The population size is $n= 650$

The sample size for graduates is $n_1 = 300$

The sample mean for graduates is $\= x _1 = 148$

The sample standard deviation for graduates is $\sigma_1 = 16$

The sample size for under-graduates is $n _2 = 350$

The sample mean for under-graduates is $\= x _2 = 153$

The sample standard deviation for graduates is $\sigma_2 = 21$

The Null hypothesis represented as

$H_0: \mu_1 - \mu_2 = 0$

The Alternative hypothesis represented as

$H_a: \mu_1 - \mu_2 < 0$

Where $\mu_1 \ and \ \mu_2$ are the population mean

Now the test statistic is mathematically represented as

$t = \frac{(\= x_1 - \= x_2 ) }{ \sqrt{ \frac{ (n_1 - 1 )\sigma_1 ^2 + (n_2 - 1)\sigma_2^2}{n_1 +n_2 -2} } * \sqrt{ \frac{1}{n_1} + \frac{1}{n_2} } }$

substituting values

$t = \frac{(148 - 153 ) }{ \sqrt{ \frac{ (300- 1 )16 ^2 + (350 - 1) 21^2}{300 +350 -2} } * \sqrt{ \frac{1}{300} + \frac{1}{350} } }$

$t = -3.37$

The p-values is mathematically evaluated as

p-value = P(Z < -3.37 ) = 0.000376

The above answer is gotten using a p-value calculator at (0.05) level of significance

Looking the p-value we see that it is less than the level of significance (0.05) so Null hypothesis is rejected

Hence there is insufficient evidence to conclude that graduate students score higher, on average, on the HPI than undergraduate students

6 0

2 years ago

Asher pays 156 every 6 weeks for piano lessons. What is the price per year for piano lessons?

Marta_Voda [28]

About 1352
There r about 52 weeks in a year
Divide 52 by 6 = 8.66666667
Multiply 8.6666667 by 156 you will get 1352 per year

6 0

2 years ago

Read 2 more answers

Bob is having a party and want to order some cake. there will be 57 guest and he wants to make sure that everyone gets a slice o

Dafna1 [17]

To find out which cake is better for the price, we need to multiply the cake amounts by how many cakes of that kind we need. You need 5 20cm cakes, so we multiply 5 by the price of the 20cm cake (13.50) to get $67.50. You need 3 25cm cakes, so 3 x 18.75 = 56.25.

20cm cake: $67.50
25cm cake: $56.25

Answer: The 25cm cake is cheaper for more people.

4 0

2 years ago

Which statements are true about the graph of y s 3x + 1 and y 2 -x + 2? Check all that apply.

Varvara68 [4.7K]

Let's go through all the options one at a time and look for the correct ones

<u>Option 1: The slope of one boundary line is 2</u>

We have 2 equations of lines, where the coefficients of are 3 and -1 respectively

because the coefficient of x denotes the slope of a line, we know that the lines have the slope 3 and -1, not 2

Hence, this option is Incorrect

<u>Option 2: Both boundary lines are solid</u>

In order for the boundary lines to be solid, the inequality must have an 'equal to', like ≤ (less than or equal to) or ≥ (greater than or equal to)

we can see that that's the case in our case and hence, this option is Correct

<u>Option 3: A solution to the system is (1, 3)</u>

To confirm this, we'll plug these coordinates into the given inequalities and see if it stands correct

y ≤ 3x + 1

3 ≤ 3(1) + 1

3 ≤ 4 which is correct because 3 is less than 4

Second equation:

y ≥ 2 - x

3 ≥ 2 - 1

3 ≥ 1

Which is also true because 3 is greater than 1

Now, we can say that (1 , 3) is a solution to the system because it satisfies both the equations and is Correct

<u>Option 4: Both inequalities are shaded below the boundary lines</u>

For an inequality to be shaded below the boundary line, it must have the ≤ inequality (in case of solid line) and < inequality (in case of dotted line)

because the second inequality listed includes the ≥ inequality, which was not mentioned above, it won't be shaded below

another way to think about it is that any 'greater than' inequality will shade everything above the line and the 'lesser than' inequality will shade below the line

which means that this option is Incorrect

<u>Option 5: The boundary lines intersect</u>

In order for the boundary lines to intersect, they must have have different slopes.

as we mentioned in the explanation of the first option, that the slopes of the lines is 3 and -1, which are different slopes

Therefore, this option is Correct

5 0

2 years ago

Read 2 more answers