Erica earned a total of $50,450 last year from her two jobs. The amount she earned from her job at the store was $1,250 more than four times the amount she earned from her job at the college.
Lets x be the amount she earned from here job at college
amount she earned at the store = 4 * amount earned at college + 1250
= 4x + 1250
Amount earned at college + amount earned at store = 50450
x + 4x + 1250 = 50450
5x + 1250 = 50450
Subtract 1250 from both sides
5x = 49200 (divide by 5)
x = 9840
she earn $9840 from her job at the college
Answer:
When p2 – 4p is subtracted from p2 + p – 6, the result is:
p2+p-6-(p2-4p)=p2+p-6-p2+4p=5p-6
To get p – 9, subtract from this result x:
5p-6-x=p-9
Solving for x:
5p-6-x+x-p+9=p-9+x-p+9
4p+3=x
x=4p+3
Answer:
1) When p2 – 4p is subtracted from p2 + p – 6, the result is 5p-6
2) To get p – 9, subtract from this result 4p+3
Step-by-step explanation:
Answer:

Step-by-step explanation:
Circumference of the column 
Circumference of a circle
Therefore:

Area of a Circle 
Since radius of the cross section of the column =9 meters
Area of the cross section of the column

Answer:
Step-by-step explanation:
Hello!
Given the linear regression of Y: "Annual salary" as a function of X: "Mean score on teaching evaluation" of a population of university professors. It is desired to study whether student evaluations are related to salaries.
The population equation line is
E(Y)= β₀ + β₁X
Using the information of a n= 100 sample, the following data was calculated:
R²= 0.23
Coefficient Standard Error
Intercept 25675.5 11393
x 5321 2119
The estimated equation is
^Y= 25675.5 + 5321X
Now if the interest is to test if the teaching evaluation affects the proffesor's annual salary, the hypotheses are:
H₀: β = 0
H₁: β ≠ 0
There are two statistic you can use to make this test, a Student's t or an ANOVA F.
Since you have information about the estimation of β you can calculate the two tailed t test using the formula:
~
= 25.1109
The p-value is two-tailed, and is the probability of getting a value as extreme as the calculated
under the distribution 
p-value < 0.00001
I hope it helps!