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maks197457 [2]
1 year ago
9

What is the common multiple of 2,960 6,400 and 2000 with full process

Mathematics
1 answer:
Mamont248 [21]1 year ago
3 0

Answer:

1184000

Step-by-step explanation:

lcm(2960,6400,2000)

prime factor:

2960=(2^4)(5)(37)\\6400=(2^8)(5^2)\\2000=(2^4)(5^3)

Take the largest power of each factor:

(2^8)(5^3)(37^1)\\=1184000

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Grant also buys bottled water and juice pouches for the picnic. There are
valentinak56 [21]

Answer:

60 of each

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water          juice

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1 year ago
If r is the midpoint of qs rs=2x-4, st= 4x-1 and rt = 8x-43 find qs
sammy [17]

Answer:

QS=68\ units

Step-by-step explanation:

step 1

Find the value of x

we know that

r is the midpoint of qs

so

QR=RS

QS=QR+RS------> QS=2RS -----> equation A

RT=RS+ST ----> equation B

see the attached figure to better understand the problem

Substitute the given values in the equation B and solve for x

8x-43=(2x-4)+(4x-1)

8x-43=6x-5

8x-6x=43-5

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x=19

step 2

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substitute the value of x

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step 3

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Remember equation A

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so

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6 0
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