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maks197457 [2]
1 year ago
9

What is the common multiple of 2,960 6,400 and 2000 with full process

Mathematics
1 answer:
Mamont248 [21]1 year ago
3 0

Answer:

1184000

Step-by-step explanation:

lcm(2960,6400,2000)

prime factor:

2960=(2^4)(5)(37)\\6400=(2^8)(5^2)\\2000=(2^4)(5^3)

Take the largest power of each factor:

(2^8)(5^3)(37^1)\\=1184000

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Write in expanded form: <br><br>5.123*10raised to power5​
ddd [48]
500000+10000+2000+300
4 0
2 years ago
When you have two shapes to compare on a coordinate plane, you can determine the scale factor, knowing that the transformation w
musickatia [10]
Assume that the initial coordinates are (x,y) and that the dilated coordinates are (x',y').

The dilation is therefore:
(x,y) ............> (x',y')

Now, let's assume that the dilation factor is k.
Therefore:
x' = kx
y' = ky

Based on the above, all the student has to do is get the initial coordinates and the final ones and then substitute in any of the above two equations to get the value of k.

Example:
Assume an original point at (2,4) is dilated to coordinates (4,8). Find the dilation factor.
Assume the dilation coefficient is k.
(x,y) are (2,4) and (x',y') are (4,8)
Therefore:
x' = kx .........> 4 = k*2 ..........> k = 2
or:
y' = ky ..........> 8 = k*4 .........> k = 2
Based on the above, the dilation coefficient would be 2.

Hope this helps :)
8 0
1 year ago
Read 2 more answers
0.75 degrees centigrade is this a positive or negative temperature?
noname [10]
This is a positive temperature.
4 0
1 year ago
The sum of an infinite geometric sequence is seven times the value of its first term.
Radda [10]

Answer:

a). r = \frac{6}{7}

b). At least 5 terms should be added.

Step-by-step explanation:

Formula representing sum of infinite geometric sequence is,

S_{\inf}=\frac{a}{1-r}

Where a = first term of the sequence

r = common ratio

a). If the sum is seven times the value of its first term.

    7a=\frac{a}{1-r}

    7=\frac{1}{1-r}

    7(1 - r) = 1

    7 - 7r = 1

    7r = 7 - 1

    7r = 6

    r = \frac{6}{7}

b). Since sum of n terms of the geometric sequence is given by,

    S_{n}=\frac{a(1-r^{n})}{1-r}

If the sum of n terms of this sequence is more than half the value of the infinite sum.

\frac{a[1-(\frac{6}{7})^{n}]}{1-\frac{6}{7}} >  \frac{7a}{2}

\frac{1-(\frac{6}{7})^{n}}{1-\frac{6}{7}}> \frac{7}{2}

\frac{1-(\frac{6}{7})^{n}}{\frac{1}{7}}> \frac{7}{2}

1-(\frac{6}{7})^{n}> \frac{7}{2}\times \frac{1}{7}

1-(\frac{6}{7})^{n}> \frac{1}{2}

-(\frac{6}{7})^{n}> -\frac{1}{2}

(\frac{6}{7})^{n}< \frac{1}{2}

(0.85714)^{n}<  (0.5)

n[log(0.85714)] < log(0.5)

-n(0.06695) < -0.30102

n > \frac{0.30102}{0.06695}

n > 4.496

n > 4.5

Therefore, at least 5 terms of the sequence should be added.

8 0
2 years ago
Three-fourths of the difference of a number and 7 is negative fifteen. The number is _______​
Vsevolod [243]

Answer:

x = -13

Step-by-step explanation:

Let the number be x. ATQ,

\dfrac{3}{4}(x-7)=-15

The above equation shows Three-fourths of the difference of a number and 7 is negative fifteen. We need to find the number.

cross multiplying both sides,

3(x-7)=-60\\\\x-7=-20\\\\x=-20+7\\\\x=-13

So, the number is -13.

4 0
2 years ago
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