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Volgvan
1 year ago
7

When you have two shapes to compare on a coordinate plane, you can determine the scale factor, knowing that the transformation w

as a dilation. Generate instructions you would give another student to determine the scale factor.
Mathematics
2 answers:
musickatia [10]1 year ago
8 0
Assume that the initial coordinates are (x,y) and that the dilated coordinates are (x',y').

The dilation is therefore:
(x,y) ............> (x',y')

Now, let's assume that the dilation factor is k.
Therefore:
x' = kx
y' = ky

Based on the above, all the student has to do is get the initial coordinates and the final ones and then substitute in any of the above two equations to get the value of k.

Example:
Assume an original point at (2,4) is dilated to coordinates (4,8). Find the dilation factor.
Assume the dilation coefficient is k.
(x,y) are (2,4) and (x',y') are (4,8)
Therefore:
x' = kx .........> 4 = k*2 ..........> k = 2
or:
y' = ky ..........> 8 = k*4 .........> k = 2
Based on the above, the dilation coefficient would be 2.

Hope this helps :)
jarptica [38.1K]1 year ago
6 0

Sample Response: Locate two corresponding ordered pairs of the two shapes. Calculate how much the pre-image values were multiplied by to obtain the image values. This is your scale factor. You can calculate this by dividing the coordinates of the mage by the corresponding coordinates of the pre-image.

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A goat is tethered by a 6 metre rope to the outside corner of a shed measuring 4 metres by 5 metres in a grassy field. What area
Naily [24]
(3/4)∗π∗62=27π
Also , the goat can reach around the corners by 2 on the short sides and 1 on long side.creating 2 90 degree sectors of additional grazing area.(1/4)∗π∗22=π
(1/4)∗π∗12=π/4
27π+π+π/4=28.25π
8 0
2 years ago
David received his allowance on Sunday. He spends 1/4 of his allowance on Monday and 2/3 of the remainder on Tuesday. What part
Marianna [84]

Answer:1/12 left

Step-by-step explanation: you should switch both into the same denominator for the fractions so that would turn into 3/12 and 8/12 then add them up to get 11/12 so he has 1/12 left

3 0
2 years ago
Cameron wondered if the average score on a final exam was different between those who texted on a regular basis during the lectu
Margarita [4]

Answer:

c. A two-tailed test should be performed since the alternative hypothesis states that the parameter is not equal to the hypothesized value.

Step-by-step explanation:

Let p1 be the average score on a final exam who texted on a regular basis during the lectures for a particular class

And p2 be the average score on a final exam who did not texted at all during the lectures for a particular class

According to the Cameron's point of interest, null and alternative hypotheses are:

H_{0}: p1 = p2

H_{a}: p1 ≠ p2

Two tailed test should be performed since the alternative hypothesis states that the parameter is not equal to the hypothesized value.

3 0
2 years ago
Solve for x: three fourths times x plus five fourths equals four times x
denis-greek [22]

Answer:

The value of x for the given expression is \dfrac{5}{13}

Step-by-step explanation:

Given as :

The statement is , three fourths times x plus five fourths equals four times x

So, \dfrac{3}{4} × x + \dfrac{5}{4} = 4 × x

<u>Now, rearranging the equation</u>

i.e 4 x -  \dfrac{3}{4} × x = \dfrac{5}{4}

Or, 4 x -  \dfrac{3 x}{4}  = \dfrac{5}{4}

Or, \dfrac{16 x - 3 x}{4}  = \dfrac{5}{4}

Or, \dfrac{13 x}{4}  = \dfrac{5}{4}

Or, 13 x = \dfrac{5}{4} × 4

Or, 13 x = 5

∴ x = \dfrac{5}{13}

Hence, The value of x for the given expression is \dfrac{5}{13} Answer

5 0
1 year ago
Which function has a range of y &lt; 3?
Setler79 [48]

Using a graphing tool

Let's graph each of the cases to determine the solution of the problem

<u>case A)</u> y=3(2^{x})  

see the attached figure N 1

The range is the interval--------> (0,∞)

y> 0

therefore

the function y=3(2^{x}) is not the solution

<u>case B)</u> y=2(3^{x})

see the attached figure N 2  

The range is the interval--------> (0,∞)

y> 0

therefore

the function y=2(3^{x}) is not the solution

<u>case C)</u> y=-2^{x}+3  

see the attached figure N 3    

The range is the interval--------> (-∞,3)  

y< 3

therefore

the function   y=-2^{x}+3    is the solution

<u>case D)</u> y=2^{x}-3  

see the attached figure N 4  

The range is the interval--------> (-3,∞)  

y>-3

therefore

the functiony=2^{x}-3 is not the solution

<u>the answer is</u>

y=-2^{x}+3

5 0
2 years ago
Read 2 more answers
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