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Volgvan
1 year ago
7

When you have two shapes to compare on a coordinate plane, you can determine the scale factor, knowing that the transformation w

as a dilation. Generate instructions you would give another student to determine the scale factor.
Mathematics
2 answers:
musickatia [10]1 year ago
8 0
Assume that the initial coordinates are (x,y) and that the dilated coordinates are (x',y').

The dilation is therefore:
(x,y) ............> (x',y')

Now, let's assume that the dilation factor is k.
Therefore:
x' = kx
y' = ky

Based on the above, all the student has to do is get the initial coordinates and the final ones and then substitute in any of the above two equations to get the value of k.

Example:
Assume an original point at (2,4) is dilated to coordinates (4,8). Find the dilation factor.
Assume the dilation coefficient is k.
(x,y) are (2,4) and (x',y') are (4,8)
Therefore:
x' = kx .........> 4 = k*2 ..........> k = 2
or:
y' = ky ..........> 8 = k*4 .........> k = 2
Based on the above, the dilation coefficient would be 2.

Hope this helps :)
jarptica [38.1K]1 year ago
6 0

Sample Response: Locate two corresponding ordered pairs of the two shapes. Calculate how much the pre-image values were multiplied by to obtain the image values. This is your scale factor. You can calculate this by dividing the coordinates of the mage by the corresponding coordinates of the pre-image.

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On this map, Oxford Street is perpendicular to_______ , and Rosewood Street is perpendicular to ________. Assume that the street
melamori03 [73]
Hi there!

We are looking for perpendicular angles, which means the angle between the streets is 90 degrees. So, each time we need to find the street that intersects the given street with a 90 degree angle.

On this map, Oxford Street is perpendicular to Waterloo St., and Rosewood Street is perpendicular to Oak St..

The answers are (in correct order): Waterloo St. and Oak St..
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6 0
2 years ago
A clock is constructed using a regular polygon with 60 sides. The polygon rotates each minute, making one full revolution each h
Maksim231197 [3]

Answer:

D. 42

Step-by-step explanation:

6 0
2 years ago
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Solution to the inequality 16x−33x<37x+27.
astra-53 [7]

<em><u>The solution to the inequality is:</u></em>

x>\frac{-1}{2}

<em><u>Solution:</u></em>

Given inequality is:

16x-33x

We have to find the solution to given inequality

\mathrm{Add\:similar\:elements:}\:16x-33x=-17x

-17x

\mathrm{Subtract\:}37x\mathrm{\:from\:both\:sides}

-17x-37x

Simplify the above inequality

-54x

\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}

Remember that, change the inequality sign if you divide or multiply both sides by a negative number

If you divide or multiply both sides by a positive number,the inequality sign will not change

\left(-54x\right)\left(-1\right)>27\left(-1\right)\\\\54x>-27

\mathrm{Divide\:both\:sides\:by\:}54

\frac{54x}{54}>\frac{-27}{54}\\\\x>-\frac{1}{2}

Thus the solution to inequality is found

3 0
2 years ago
Out of 106 total sophomores, there were forty-eight boys who received either an a, b, or c on their first math test. out of the
Musya8 [376]
<span>The table should have the titles: "Grades" for the horizontal axis and "Gender" for the vertical axis. The values for "Grades" are A, B, & C. The values for "Gender" are Boys and Girls. The information contained within the table should be as follows: 12 boys received an A, 24 boys received a B, 12 boys received a C; 16 girls received an A, 30 girls received a B, and 12 girls received a C. There should be a "Total" row at beneath the "Gender" section showing that there were 28 A's, 54 B's, and 24 C's. There should be an additional "Total" column at the end of "Grades" showing that there are 48 boys and 52 girls.</span>
6 0
2 years ago
Read 2 more answers
suppose you could make a single "lump sum" deposit of $3679, in an investment that provides an annual percentage rate(apr) of 4%
yaroslaw [1]

Answer:

\$5,698.30  

Step-by-step explanation:

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  (future value)

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=11\ years\\ P=\$3,679\\ r=4\%=4/100=0.04\\n=365  

substitute in the formula above

A=3,670(1+\frac{0.04}{365})^{365*11}  

A=\$5,698.30  

3 0
2 years ago
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