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2 years ago

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Between which pair of numbers is the exact product of 379 and 8?

2 answers:

klasskru [66]2 years ago

4 0

The complete question is

Between which pair of numbers is the exact product of 379 and 8?

A between 2,400 and 2,500

B between 2,400 and 2,800

C between 2,400 and 3,000

D between 2,400 and 3,200

Find the product

Multiply 379 by 8

$379*8=3,032$

therefore

$2,400$

the answer is the option

D between $2,400$ and $3,200$

nata0808 [166]2 years ago

3 0

<span>379 times 8 is 3032. This result, 3032 is between 3031 and 3033, so the answer is that the exact product of 379 and 8 is between 3031 and 3033.</span>

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The drama club at Del Rosa Middle School is having a production.

Firdavs [7]

Answer:

320 Student Tickets

180 Adult Tickets

Step-by-step explanation:

You can solve this problem by using system of equations. First, we need to figure out our equations.

Equation 1: x as students and y as adults

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We get this equation because the total tickets sold was 500. The x represents the students sold to students, and the y represents the tickets sold to adults.

Equation 2:

$3x+5y=1850$

We get this equation based on the prices. Each student ticket costs $3, and each adult ticket costs $5. The total amount earned was $1850.

Now that we have out equations, we can use system of equations to find our students and adults.

$x+y=500$

$3x+5y=1860$

Typically elimination is the easiest strategy because you are able to cross out variables.

$3(x+y=500)$

$3x+5y=1860$

Becomes:

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$3x+5y=1860$

We see that both equations now have 3x. We can cancel out 3x.

$-2y=-360$

$y=180$

Now that we know y=180, we can plug it back into one of our equations to find x.

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320 student tickets and 180 adult tickets were sold.

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2 years ago

Which values of x and y would make the following expression represent a real number? (4+5i)(x+yi)

algol [13]

Answer:

So x=4 and y=-5 would work.

Step-by-step explanation:

When you multiply complex conjugates, you get a real result.

Example:

$(a+bi)(a-bi)=a^2-b^2i^2=a^2+b^2$

I replace $i^2$ with -1 since $i^2=-1$ .

$a^2+b^2$ is a real number (there is no imaginary part, no i).

So what is the conjugate of 4+5i?

4-5i

So x=4 and y=-5 would work.

A multiple of the complex conjugate would work as well.

$(a+bi)(ca-cbi)$

$c(a+bi)(a-bi)$

$c(a^2-b^2i^2)$

$c(a^2+b^2)$

This is still a real number; there is no imaginary part,no i.

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2 years ago

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slega [8]

Answer:

B

Step-by-step explanation:

This is the answer because a function cannot have an x-value that produces more than one y-value.

The equation is in slope-intercept form (y = mx + b), where F is y and C is x.

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2 years ago

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Let a4+a8+a12+a16=224. Find the sum of first 19 term in sequence.

Tomtit [17]

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$\ldots$

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Then we can write

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$\displaystyle\sum_{n=1}^{19}a_n=\sum_{n=1}^{19}\big(a+(n-1)k\big)=19a+k\sum_{n=1}^{18}n=19a+171k$

If we knew one more term in the sequence, we could determine the value of $k$ and derive the value of $a$ (if the first term $a_1$ is not immediately given), and then go on to find an exact numeric value for the sum.

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Pachacha [2.7K]

He receives 8.5% <span>commission on sales from $70,000 to $100,000, therefore the commission is:
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