Question

Each of the faces of a fair six-sided number cube is numbered with one of the numbers 1 through 6 with a different number appearing on each face. Two such number cubes will be tossed, and the sum of the numbers appearing on the faces that land up will be recorded. What is the probability that the sum will be 4, given that the sum is less than or equal to 6?

Answer 1

Answer:

0.2 = 20%

Step-by-step explanation:

The possibilities that give us a sum of 6 or less are:

(1,1), (1,2), (1,3), (1,4), (1,5),

(2,1), (2,2), (2,3), (2,4),

(3,1), (3,2), (3,3),

(4,1), (4,2),

(5,1)

(Total of 15 possibilities)

The possibilities that have a sum of 4 are:

(1,3), (2,2), (3,1)

(Total of 3 possibilities)

So, the probability that the sum will be 4, given that the sum is less than or equal to 6 is:

P = 3/15 = 0.2 = 20%