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Tom [10]
1 year ago
14

The Smiths bought new furniture that cost $3,298.00. The store offered them

Mathematics
1 answer:
ad-work [718]1 year ago
7 0

Answer:

10.99%.

Step-by-step explanation:

We have been given that the Smiths bought new furniture that cost $3,298.00. The store offered them  an option of putting $600 down and making equal payments of $300 a month  for 10 months.

First of all, we will find amount paid by down-payments in 10 months.

\$300\times 10=\$3,000

Total amount paid by Smiths: \$3,000+\$600=\$3,600.

Now we will find amount paid in interest by subtracting initial amount from total amount.

\text{Amount paid in interest}=\$3,600-\$3,298

\text{Amount paid in interest}=\$302

10 months = 10/12 year =5/6 year.

Now, we will use simple interest formula to solve for interest rate.

I=Prt

\$302=\$3,298*r*\frac{5}{6}

\$302=r*\frac{\$16,490}{6}

\$302*\frac{6}{\$16,490}=r*\frac{\$16,490}{6}*\frac{6}{\$16,490}

\frac{1,812}{\$16,490}=r

r=\frac{1,812}{\$16,490}

r=0.1098847786

r=0.1098847786\times 100

r=10.98847786\%

r\approx 10.99\%

Therefore, the annual interest rate is 10.99%.

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To measure the price difference in dollars is simple, just subtract the old price from the new one:

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Answer:

II. This finding is significant for a two-tailed test at .01.

III. This finding is significant for a one-tailed test at .01.

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Step-by-step explanation:

1) Data given and notation    

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\sigma=2.5 represent the population standard deviation    

n=25 sample size    

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\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

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Null hypothesis:\mu = 18    

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And for part III we have a one tailed test with the following hypothesis:

Null hypothesis:\mu \leq 18    

Alternative hypothesis:\mu > 18  

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z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

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We can replace in formula (1) the info given like this:    

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First we need to calculate the degrees of freedom given by:  

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5) Conclusion    

I. This finding is significant for a two-tailed test at .05.

Since the p_v. We reject the null hypothesis so we don't have a significant result. FALSE

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Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

III. This finding is significant for a one-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

So then the correct options is:

d. II and III only

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