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Oxana [17]
2 years ago
14

Which statement best summarizes the central idea of “Applications of Newton’s Laws”? Newton’s laws can explain the forces that o

ccur between objects every day. Newton’s laws are useful for explaining why we should make good decisions. People should use caution when moving objects, due to objects’ inertia. Newton’s laws are outdated and cannot be used for present-day problems and situations.
Mathematics
2 answers:
Kisachek [45]2 years ago
8 0

Step-by-step explanation:

Newtons has given three laws of motion. The concept of gravitational force is also given by Newton. According to him the force acting between two objects is given by :

F=G\dfrac{m_1m_2}{r^2}.............(1)

Where

m₁ and m₂ are masses of two objects

r = distance between them

G = universal gravitational constant

Equation 1 shows the force acting between the objects in the universe. So, Newton's laws explains about the forces acting between objects in our daily lives.

nadya68 [22]2 years ago
5 0
Answer: <span>Newton’s laws can explain the forces that occur between objects every day. 

Newton's Laws are known as the "Three Laws of Motion." They address inertia, force, and gravity. Because these are all phenomenons that occur every day, that is the correct answer.
</span>
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Given two vectors a⃗ =4.00i^+7.00j^ and b⃗ =5.00i^−2.00j^ , find the vector product a⃗ ×b⃗ (expressed in unit vectors). what is
FinnZ [79.3K]

The vector product of \boxed{a \times b =  - 43\hat k} and the magnitude of a \times b is \boxed{43}.

Further explanation:

Given:

Vector a is \vec a = 4.00\hat i + 7.00\hat j.

Vector b is \vec b = 5.00\hat i - 2.00\hat j.

Explanation:

The cross product of a \times b can be obtained as follows,

\begin{aligned}a \times b &= \left| {\begin{array}{*{20}{c}}{\hat i}&{\hat j}&{\hat k} \\4&7&0\\5&{ - 2}&0 \end{array}}\right|\\&= \hat i\left( {0 - 0} \right) - \hat j\left( {0 - 0} \right) + \hat k\left( { - 9 - 35} \right)\\&= 0\hat i - 0\hat j - 43\hat k\\&= - 43\hat k\\\end{aligned}

The vector can be expressed as follows,

a \times b =  - 43\hat k

The magnitude of a \times bcan be obtained as follows,

\begin{aligned}\left| {a \times b} \right| &= \sqrt {{0^2} + {0^2} + {{\left( { - 43} \right)}^2}}\\&= \sqrt {{{43}^2}}\\&= 43\\\end{aligned}43404

The vector product of \boxed{a \times b =  - 43\hat k} and the magnitude of a \times b is \boxed{43}.

Learn more:

  1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
  2. Learn more about equation of circle brainly.com/question/1506955.
  3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Vectors

Keywords: two vectors, vector product, expressed in unit vectors, magnitude, vector a, vector b, a=4.00i^+7.00j^, b=5.00i^-2.00j^, unit vectors, vector space.

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1) y intercept is when x=0, so 3y=36, y=12

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