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labwork [276]
2 years ago
6

0.07 is 1/10 of what

Mathematics
2 answers:
DIA [1.3K]2 years ago
8 0

Answer:

0.7

Step-by-step explanation:

Let x be our required number.

We are asked to find a number such that 1/10 of the number equals 0.07.

1/10 of the required number would be \frac{1}{10}x.

Now, we will equate \frac{1}{10}x with 0.07 to find our required number.

\frac{1}{10}x=0.07

10*\frac{1}{10}x=10*0.07

x=0.7

Therefore, 0.07 is 1/10 of 0.7.

Whitepunk [10]2 years ago
6 0
0.07 * 10 = 0.7

Hope this helps! :)
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20+5=25 then 25-4.67=20.33 so then you do 20.33/4.5=4.5 so the cost for one pound of fruit is $4.57. Hope this helps :)
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2 years ago
A survey of a group of seventh graders and a group of teachers at a local middle school asked how many siblings they each have.
kvasek [131]

Answer:

The center of the data is to the right of the dot plot for both teachers and students.

There is a greater variation in the data for teachers than for students.

The center of the data for students has a value less than that of the center of the data for teachers.

Step-by-step explanation:

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2 years ago
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Which evidence from "Charles" supports the inference that Laurie enjoys that his parents believe his stories about Charles? Sele
ratelena [41]

Answer:

'Well, Charles was bad again today.' He grinned enormously.” "'Well, he certainly likes kindergarten,' I said. 'He talks about it all the time.'"

Step-by-step explanation:

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1 year ago
A sample of 900 college freshmen were randomly selected for a national survey. Among the survey participants, 372 students were
Rufina [12.5K]

Answer:

a) ME=2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.0423

b) 0.413 - 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.371

Step-by-step explanation:

1) Data given and notation  

n=900 represent the random sample taken    

X=372 represent the students were pursuing liberal arts degrees

\hat p=\frac{372}{900}=0.413 estimated proportion of students were pursuing liberal arts degrees

\alpha=0.01 represent the significance level

z would represent the statistic (variable of interest)    

p_v represent the p value (variable of interest)    

p= population proportion of students were pursuing liberal arts degrees

2) Solution to the problem

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

The margin of error is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

If we replace we have:

ME=2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.0423

And replacing into the confidence interval formula we got:

0.413 - 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.371

0.413 + 2.58 \sqrt{\frac{0.413(1-0.413)}{900}}=0.455

And the 99% confidence interval would be given (0.371;0.455).

We are confident (99%) that about 37.1% to 45.5% of students were pursuing liberal arts degrees.

7 0
2 years ago
As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of 1.11.
Elis [28]

Answer:

124.67cm³

Step-by-step explanation:

==>Given:

Dimensions of current can:

Height (h) = 12cm

Diameter = 6cm (radius = 3cm)

Volume of current can (V1) = 339.12 cm³

Dimensions of future cans to be increased multiple of 1.11:

height = 12cm × 1.11 = 13.32 cm

radius = 3cm × 1.11 = 3.33 cm

Volume of future can (V2) = πr²h = 3.14*3.33²*13.32

= 3.14*11.0889*13.32 = 463.791025

V2 ≈ 463.79 cm³

==>Find how much more would new cans hold = Volume of new can - volume of current can

= 463.79 cm³ - 339.12 cm³

= 124.67cm³

5 0
2 years ago
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