Answer:
Step-by-step explanation:
We want to determine a 95% confidence interval for the mean salary of all graduates from the English department.
Number of sample, n = 400
Mean, u = $25,000
Standard deviation, s = $2,500
For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean ± z × standard deviation/√n
It becomes
25000 ± 1.96 × 2500/√400
= 25000 ± 1.96 × 125
= 25000 ± 245
The lower end of the confidence interval is 25000 - 245 =24755
The upper end of the confidence interval is 25000 + 245 = 25245
Therefore, with 95% confidence interval, the mean salary of all graduates from the English department is between $24755 and $25245
Answer=6
Given the information, the following equation can be made, where x is equal to the number of cases she needs to buy.
160=16+24x
subtract 16 from both sides
144=24x
divide both sides by 24
6=x
She will have to buy 6 cases to have a total of 160 water bottles.
Answer:
N + D = 175
.05N + .10D = $13.30
Step-by-step explanation:
You need a system of equations to get the correct answer that applies to both constraints.
