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V125BC [204]
2 years ago
5

A concert venue offers tickets in 333 zones: orchestra, grand tier, and balcony. Tickets in the orchestra zone are most expensiv

e, and tickets in the balcony zone are least expensive. Managers of the venue want to survey approximately 150150150 guests at an upcoming concert about their overall experience. They want to take a stratified random sample of guests based on the venue's zones. Which of these strategies will accomplish their intended design?
Mathematics
1 answer:
Sonbull [250]2 years ago
3 0

Answer:

Randomly select 50 tickets from each zone and invite those guests to participate in the survey.

Step-by-step explanation:

I hope this helped

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John is planning to purchase a new car that costs $15,500. On average, a new car loses 11% of its value the moment that it is dr
Levart [38]

15500 times 0.37 is 5735.

$5735

The 11% statement is extra information.

4 0
2 years ago
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Hence explain how you know that x^2-8x+20 is always positive
Tasya [4]

If you complete the square you get

{(x - 4) }^{2}  + 4

and as any number squared is positive and 4 is positive, the result must be positive

6 0
2 years ago
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Rachael ordered early learning software for her daughter from an online retailer. Each item costs $6.50, and there is a shipping
natta225 [31]

Answer:

Step-by-step explanation:

(a)

Total cost = (7 items * Cost per item) + Shipping fee = 7*6.5 + 8.5 = $54

(b)

Modelling the above equation with symbols:

c = s*6.5 + 8.5 = 6.5s + 8.5

(c)

For a total cost of 80$, c = 80:

80 = 6.5s + 8.5

Calculating, we get:

s =  11 items

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4 0
2 years ago
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Suppose that a random sample of size 100 is to be selected from a population with mean 50 and standard deviation 8. What is the
maksim [4K]

Answer:

0.159

Step-by-step explanation:

Given that:

Sample size (n) = 100

Population mean(pm) = 50

Standard deviation (s) = 8

Probability that Sample mean (m) will be greater Than 50.8

Using the relation :

(sample mean - population mean) / (standard deviation /sqrt(n))

P(m > 50.8)

Z = (50.8 - 50) / (8/ sqrt(100))

Z = 0.8 / (8/ 10)

Z = 0.8 / 0.8

Z = 1

P(Z > 1) = 0.15866 ( Z probability calculator)

Hence,

P(Z > 1) = 0.159 ( 3 decimal places)

7 0
2 years ago
Un kg de banane costa cat doua kilograme de portocale . Un restaurant a cumparat 30 de kg de portocale si 45 de kg de banane , p
Nimfa-mama [501]

Answer:

<h2>One kilogram of oranges cost $3.</h2>

Step-by-step explanation:

The problem states

  • 1 kilogram of bananas costs as much as 2 kilograms of oranges. (1 \ kg \ bananas = 2 \ kg  \ oranges)
  • 30 kilograms of oranges plues 45 kilograms of bananas cost $360.

Let's call x one kilogram bananas and y one kilogram oranges. The cost is related by

x=2y

Also, we know by given

45x+30y=360

Replacing the first equation into the second one, we have

45(2y)+30y=360\\90y+30y=360\\120y=360\\y=\frac{360}{120}\\ y=3

Then, we find the other value

x=2(3)=6

Therefore, one kilogram of oranges cost $3.

5 0
2 years ago
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