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stira [4]
2 years ago
14

Rory is staying in a cabin on a hill 300 feet above sea level. She walks down the hill to the water’s edge. The equation of her

average change in elevation over time is e = 300 – 10t, where t is the time in minutes since she left the cabin, and e is her elevation with regard to sea level. Which values are viable points, and what are their values in the table relating t and e?

Mathematics
2 answers:
Anastasy [175]2 years ago
8 0

For this problem, we plug in the <em>numbers for t</em> and the <em>appropriate letters for e</em> to the equation <em>e = 300 - 10t</em>.

a) a = 300 - 10(-2)

simplify: a = 300 + 20

simplify: a = 320 ft.

But, this is not a viable point because when t≤0, she doesn't move anywhere, thus, should consistently be 300 ft.

b) b = 300 - 10(3.5)

simplify: b = 300 - 35

simplify: b = 265 ft.

c) c = 300 - 10(30)

simplify: c = 300 - 300

simplify: c = 0 ft.

Lubov Fominskaja [6]2 years ago
3 0

A) not viable

B) 265

C) 0

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cp  percent  fraction   sp

          -12         88/100  16. 50

100*16.50 /88= 18.75

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If you increase your current quality score of 85% by 7%,
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85 x 0.07 = 5.95

Total = 85 + 5.95 = 90.95%
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Alison wants to distribute the carnations and roses equally among the 6 flower shops. Factor the expression from Part A using 6
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6

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1 year ago
A composite figure is comprised of a square, trapezoid, and a rectangle. The square has side lengths of 10 centimeters. The trap
Evgesh-ka [11]

The area of the composite figure is 264 square centimeters, if a composite figure comprised of a square, trapezoid and a rectangle.

Step-by-step explanation:

The given is,

                   Dimensions of square has length of 10 cm

                   Trapezoid has base lengths of 8 cm and 14 cm

                   The length of the trapezoid is 4 cm

                   Rectangle has side length of 20 cm and 6 cm

Step:1

            Area of composite figure = Area of square + Area of Trapezoid

                                                                + Area of rectangle.......................(1)

Step:2

                  Formula for area of square,

                                                 A_{square} = a^{2}

                 where, a - side of length = 10 cm

                                                             =10^{2}

                                                            =100

                    Area of square, A_{square} = 100 Square centimeter

Step:3

                Formula for area of Trapezoid,

                                            A_{Trapezoid} = \frac{a+b}{2} h.......................................(2)

                    Where, a - 8 cm

                                 b - 14 cm

                                 h - 4 cm

                 From equation (2)

                                                            = \frac{8+14}{2} 4

                                                            = (11)(4)

                                                            = 44

         Area of  Trapezoid, A_{Trapezoid} = 44 square centimeters

Step:4

             Formula for area of rectangle,

                                            A_{Rectangle} =lb......................................(3)

            Where, l = 20 cm

                        b = 6 cm

           Equation (3) becomes,

                                                            = (20)(6)

                                                            = 120

            Area of rectangle, A_{Rectangle} = 120 square centimeters

Step:5

            From Equation (1),

                     A_{Composite} = 100 + 44 + 120

                                     = 264 square centimeters

Result:

            The area of the composite figure is 264 square centimeters, if a composite figure comprised of a square, trapezoid and a rectangle.

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Answer:

The answer in the procedure

Step-by-step explanation:

Let

A1 ------> the area of the first square painting

A2 ---->  the area of the second square painting

D -----> the difference of the areas

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A1=81x^{2}-90x-25

A2=25x^{2}+30x+9

case 1) The area of the second square painting is greater than the area of the first square painting

The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting

D=A2-A1

D=(25x^{2}+30x+9)-(81x^{2}-90x-25)

D=(-56x^{2}+120x+34)

case 2) The area of the first square painting is greater than the area of the second square painting

The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting

D=A1-A2

D=(81x^{2}-90x-25)-(25x^{2}+30x+9)

D=(56x^{2}-120x-34)

4 0
2 years ago
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