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Zielflug [23.3K]

1 year ago

15

Before school, janine spends 1/10 hour making the bed, 1/5 hour getting dressed, and 1/2 hour eating breakfast. What fraction of

an hour does she spend doing these activities

1 answer:

N76 [4]1 year ago

6 0

4/5 of an hour spent

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Mr. Stephens uses 100 N of force to push the snake tank straight up 2 meters.

ArbitrLikvidat [17]

What is the question?

8 0

2 years ago

The editor of a textbook publishing company is deciding whether to publish a proposed textbook. Information on previous textbook

kogti [31]

Answer:

34.86% probability that it will be huge success

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)}$

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Receiving a favorable review.

Event B: Being a huge success.

Information on previous textbooks published show that 20 % are huge successes

This means that $P(B) = 0.2$

99 % of the huge successes received favorable reviews

This means that $P(A|B) = 0.99$

Probability of receiving a favorable review:

20% are huge successes. Of those, 99% receive favorable reviews.

30% are modest successes. Of those, 70% receive favorable reviews.

30% break even. Of those, 40% receive favorable reviews.

20% are losers. Of those, 20% receive favorable reviews.

Then

$P(A) = 0.2*0.99 + 0.3*0.7 + 0.3*0.4 + 0.2*0.2 = 0.568$

Finally

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)} = \frac{0.2*0.99}{0.568} = 0.3486$

34.86% probability that it will be huge success

4 0

1 year ago

For a normally distributed random variable x with m = 75 and s = 4, find the probability that 69 < x < 79 Use the table to

nalin [4]

10-14-19-12-14-18-10-15-15

6 0

1 year ago

An animal park has lions, tigers and zebras. 20% of the animals are lions and half of the animals are zebras. If there are 120 a

RoseWind [281]

Answer:

$36\ tigers$

Step-by-step explanation:

Let

x ----> the number of lions

y ----> the number f tigers

z ----> the number of zebras

we know that

$x+y+z=120$ ----> equation A

Remember that

$20\%=20/100=0.20$

$50\%=50/100=0.50$

To find out the number of lions, multiply the total animals by the percentage of lions

$x=0.20(120)=24\ lions$

To find out the number of zebras, multiply the total animals by the percentage of zebras

$z=0.50(120)=60\ zebras$

Substitute the value of x and the value of z in equation A and solve for y

$24+y+60=120$

$y+84=120$

$y=36\ tigers$

6 0

1 year ago

Mr. Johnson currently has a square garden. It is in his garden and into a range of 5 feet shorter than three times shorter than

Vlad [161]

Answer:

The Dimension of new garden is $25 \ feet\ \times 10\ feet.$

Step-by-step explanation:

Given:

Perimeter of new garden = 70 feet.

Let the length of the new garden be 'l'.

Also Let the width of the new garden be 'w'.

We need to find the dimension of new garden.

Now Given:

Length is 5 feet shorter than three times it width.

framing the equation we get;

$l =3w-5 \ \ \ \ equation\ 1$

Now we know that;

Perimeter of rectangle is equal to twice the sum of length and width.

framing in equation form we get;

$2(l+w)=70$

Now Diving both side by 2 using Division property of equality we get;

$\frac{2(l+w)}2=\frac{70}{2}\\\\l+w =35$

Now Substituting equation 1 in above equation we get;

$3w-5+w=35\\\\4w-5=35$

Adding both side by 5 Using Addition Property of equality we get'

$4w-5+5=35+5\\\\4w=40$

Now Diving both side by 4 using Division property of equality we get;

$\frac{4w}{4}=\frac{40}{4}\\\\w=10\ ft$

Now Substituting the value of 'w' in equation 1 we get;

$l =3w-5\\\\l =3\times10-5\\\\l = 30-5\\\\l= 25\ ft$

Hence The Dimension of new garden is $25 \ feet\ \times 10\ feet.$

3 0

2 years ago