Question

The label on a ceiling lighting fixture warns you to use a lightbulb of 60 watts or less. The voltage to the lightbulb is 120 volts. An intern calculated how much amperage a bulb of the maximum allowed wattage will draw. You are checking her work, shown below. If there is an error, what is the first step that has an error, and why is it an error?

Answer 1

Answer:

0.5 A

Step-by-step explanation:

Hi,

I believe the question is incomplete. However, as per the information provided:

The simplest way to calculate the Current (unit is Amperage), is understanding the relationship between the three: Power, Voltage and Current.

(Quick Tip: W=AV; where W -> Watts (Power), A -> Ampere (Current), V -> Volts (Voltage))

Using the formula we calculate the Ampere:

W = A x V

60 = A x 120

60/120 = A (We divide the equation be 120)

0.5 = A  (Simply reduce the fraction 60/120  = 1/2 = 0.5)

Tip: