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gulaghasi [49]
2 years ago
8

Crispy Clover, a popular vegetarian restaurant, introduced a new menu that has 20\%20%20, percent more dishes than the previous

menu. The previous menu had DDD dishes.
Which of the following expressions could represent how many dishes Crispy Clover's new menu has?
Mathematics
1 answer:
amm18122 years ago
5 0

<em><u>Question:</u></em>

Crispy clover, a popular vegetarian restaurant, introduced a new menu that had 20% more dishes than the previous menu. The previous menu had D dishes. Which of the following expressions could represent how many dishes crispy clovers new menu has?

<em><u>Answer:</u></em>

<em><u>The expression could represent how many dishes crispy clovers new menu has is:</u></em>

D + \frac{1}{5}D \text{ or } 1.2D

<em><u>Solution:</u></em>

Given that,

The new menu had 20% more dishes than the previous menu

The previous menu had D dishes

Therefore,

Previous menu = D dishes

New menu = 20 % more dishes than previous menu

Which means,

New menu = 20 % of previous menu + previous menu

Therefore,

New menu = 20 % of D + D

Solve the above equation

New\ menu = 20 \% \times D + D\\\\New\ menu = \frac{20}{100} \times D + D\\\\New\ menu = 0.2 \times D + D\\\\New\ menu = 0.2D + D = \frac{D}{5} + D = 1.2D

Therefore, new menu has 1.2D dishes

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"Consider the probability distribution of X, where X is the number of job applications completed by a college senior through the
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Answer:

Option b

Step-by-step explanation:

Given that the probability distribution of X, where X is the number of job applications completed by a college senior through the school’s career center.

 Expected observed Diff

x p(x) p(x)*1000  

   

0 0.002 2  

1 0.011 11 14 -3

2 0.115 115 15 100

3 0.123 123 130 -7

4 0.144 144  

5 0.189 189  

6 0.238 238  

7 0.178 178  

   

1 1000

We find that there is a large difference in 2 job application

Hence option b is right.  

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2 years ago
What are the lengths of sides KN and NM of the kite?<br> KN = <br> units<br> NM = <br> units
Natalka [10]
Y+10= 2y+5
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5=y

Plug this in
(5)+10=15 for KN


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2(7)+6
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7 0
2 years ago
Read 2 more answers
32​% of U.S. adults say they are more likely to make purchases during a sales tax holiday. You randomly select 10 adults. Find t
Lorico [155]

Answer:

A.  21.06%

B. 66.88%

C. 81.56%

Step-by-step explanation:

There are two possible answer for the question asked, yes(more likely to make purchases) or no. The probability for a random adults answer yes to the question is 32% so the probability that the adults answer no is 68%.

(a) exactly​ two

There is only one case for this question, 2 people say yes and 8 people say no. The calculation for this problem will be:

2P10 * P(yes)^2 * P(no)^8= 10!/2!8!* 32%^2  * 68%^8 = 0.21066= 21.06%

(b) more than​ two

There are a lot of case for more than two, its easier to find out the negation of the probability which is "two or less". Case that fulfill "two or less" will be: 2 yes and 8 no

1 yes and 9 no

0 yes and 10 no

The calculation for the negation will be:

~P(X)= 0P10 * P(yes)^0 * P(no)^10   +   1P10 * P(yes)^1 * P(no)^9   +  2P10 * P(yes)^2 * P(no)^8  =

10!/0!10!* 32%^0  * 68%^10    +   10!/1!9!* 32%^1  * 68%^9   +   10!/2!8!* 32%^2  * 68%^8

0.02113 + 0.09947 + 0.21066  =  0.33126= 33.12%

Since its the negation, you need to subtract 1 with the negation

P(X)= 1 - ~P(X)

P(X)= 1 - 33.12%= 66.88%

(c) between two and​ five, inclusive

Same formula as above, but the case is:

2 yes and 8 no

3 yes and 7 no

4 yes and 6 no

5 yes and 5 no

The calculation will be:

2P10 * P(yes)^2 * P(no)^8 + 3P10 * P(yes)^3 * P(no)^7 + 4P10 * P(yes)^4 * P(no)^6 + 5P10 * P(yes)^5 * P(no)^5 =

10!/2!8!* 32%^2  * 68%^8    +   10!/3!7!* 32%^3  * 68%^7   +   10!/4!6!* 32%^4  * 68%^6  +  10!/5!5!* 32%^5  * 68%^5

0.21066 + 0.26435 + 0.21770 + 0.1229= 0.81561= 81.56%

8 0
2 years ago
One hundred teachers attended a seminar on mathematical problem solving. The attitudes of representative sample of 12 of the tea
andrew11 [14]

Answer:

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b) 3.25

c) 1.5

d) -5.23

Step-by-step explanation:

We are given the following in the question:

4, 7, -1, 1, 0, 5, -2, 2, -1, 6, 5, -3

a) mean of score change

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

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b) standard deviation for this population

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.

Sum of squares of differences = 126.92

\sigma = \sqrt{\frac{126.92}{12}} = 3.25

c) median change score

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Sorted data: -3, -2, -1, -1, 0, 1, 2, 4, 5, 5, 6, 7

Median =

\dfrac{6^{th} + 7^{th}}{2} = \dfrac{1+2}{2} = 1.5

d) change score that is 2.2 standard deviations below the mean.

x = \mu - 2.2(\sigma)\\x = 1.92-2.2(3.25)\\x = -5.23

4 0
2 years ago
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