Let x = width
x+1 is then the length
2x+2(x+1)=66
2x+2x+2=66
4x=64
x=16
deck will be 16x17, nice for a BBQ. :)
B. The total area painted is 864; they must buy two cans of paint.
Step-by-step explanation:
Step 1:
A rectangle's area can be calculated by multiplying its length and its width. The wall is made up of 5 different types of rectangular walls. All walls are 8 feet tall but the length varies.
Step 2:
The area of the 20 feet long wall = 
The area of the 10 feet long wall = 
The area of the 5 feet long wall = 
The area of the 4 feet long wall = 
The area of the 15 feet long wall = 
The area of all the walls = 432 square feet.
Since there are two sides for every wall, total area =
square feet.
Step 3:
If one paint can covers 500 square feet,
the number of cans required to paint 864 square feet =
cans.
so 2 paint cans are needed to paint 864 square feet which is option B.
The question is incomplete. Here is the complete question:
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.
Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?
Answer:
40.13%
Step-by-step explanation:
Let 'A' be the event of not missing a target in 10 attempts.
Therefore, the complement of event 'A' is 
Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.
Now, 
We know that the sum of probability of an event and its complement is 1.
So, 
Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.
Answer:
c
Step-by-step explanation:
we have to use a mean to describe the center
Answer:
C. 67.5 to 72.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The width of the interval is determined by it's margin of error, which is given by the following formula:

So, as n increases, the margin of error decreases, and the interval gets smaller.
Using 10,000 bootstrap samples for the distribution:
We increase the sample size, which means that the interval gets smaller.
We had 67 to 73, since it got smaller, it will be from a value higher than 67 to a value lower than 73.
So the correct answer is:
C. 67.5 to 72.