Geometry:

Roberto wants to display his 18 sports cards in an album. Some pages hold 2 cards and others hold 3 cards. How many different wa

WITCHER [35]

65 = number of different arrangements of 2 and 3 card pages such that the total number of card slots equals 18. 416,154,290,872,320,000 = number of different ways of arranging 18 cards on the above 65 different arrangements of page sizes. ===== This is a rather badly worded question in that some assumptions aren't mentioned. The assumptions being: 1. The card's are not interchangeable. So number of possible permutations of the 18 cards is 18!. 2. That all of the pages must be filled. Since the least common multiple of 2 and 3 is 6, that means that 2 pages of 3 cards can only be interchanged with 3 pages of 2 cards. So with that said, we have the following configurations. 6x3 card pages. Only 1 possible configuration. 4x3 cards and 3x2 cards. These pages can be arranged in 7!/4!3! = 35 different ways. 2x3 cards and 6x2 cards. These pages can be arranged in 8!/2!6! = 28 ways 9x2 card pages. These can only be arranged in 1 way. So the total number of possible pages and the orders in which that they can be arranged is 1+35+28+1 = 65 possible combinations. Now for each of those 65 possible ways of placing 2 and 3 card pages such that the total number of card spaces is 18 has to be multiplied by the number of possible ways to arrange 18 cards which is 18! = 6402373705728000. So the total amount of arranging those cards is 6402373705728000 * 65 = 416,154,290,872,320,000

6 0

2 years ago

Farmers mowed 60 acres of grass a day instead of 50 and managed to finish the task one day earlier than planned. What is the are

schepotkina [342]

300 acres. because multiply 60 by 5.

6 0

2 years ago

While at a carnival, Andrew comes across a game that involves rolling a die. According to the game's rules, if the number rolled

Reptile [31]

Answer:

he can expect to lose 0.5$

Step-by-step explanation:

To solve this problem we must calculate the expected value of the game.

If x is a discrete random variable that represents the gain obtained when rolling a dice, then the expected value E is:

$E =\sum xP (x)$

When throwing a dice the possible values are:

x: 1→ -$9; 2→ $4; 3→ -$9; 4→ $8; 5→ -$9; 6→ $12

The probability of obtaining any of these numbers is:

$p=\frac{1}{6}$

The gain when obtaining an even number is twice the number.

The loss to get an odd number is $ 9

So the expected gain is:

$E=-9*\frac{1}{6}-9*\frac{1}{6}-9*\frac{1}{6} + 4*\frac{1}{6} + 8*\frac{1}{6} + 12*\frac{1}{6}\\\\E =-27*\frac{1}{6} + 24*\frac{1}{6}\\\\E=-3*\frac{1}{6}\\\\E=-$0.5$

4 0

2 years ago

after 24.0 days, 2.00 milligrams of an original 128.0 milligram sample remain. what is the half-life of the sample?

coldgirl [10]

(1/2)n = 0.015625
n log 0.5 = log 0.015625
n = log 0.5 / log 0.015625
n = 624 days / 6 half-lives = 4.00 days (the length of the half-life)

6 0

2 years ago

Suppose we want to choose 2 colors without replacement from the 3 colors

Rzqust [24]

Question:

Suppose we want to choose 3 colors, without replacement, from the red, blue, green, and purple.

(a)How many ways can this be done, if the order of the choices is taken into consideration?

(b)How many ways can this be done, if the order of the choices is not taken into consideration?

Answer:

(a) 6 choices

(b) 3 Choices

Step-by-step explanation:

Given:

3 Colors

Order of choice : Red, Blue, Green

(a) Order of the choices taken into consideration :

When we are picking the first colour there are 3 color choice.

When we are picking second colour there are 2 choice and so on.

Therefore, total choices are = 3*2 = 6 choices

(b) Order of the choices not taken into consideration :

When to take this option we choose as $3 \times 2$ and the remove the duplicates

Therefore, choices are = $\frac{(3 \times 2)}{(1 \times 2)}$ = $\frac{6}{2}$ = 3 Choices

7 0

2 years ago