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sashaice [31]
2 years ago
6

Explain how to estimate 368+231 in two different ways

Mathematics
2 answers:
Dennis_Churaev [7]2 years ago
6 0
400+200 or add 368+231= 599 and you round your answer, woulb be 600
fredd [130]2 years ago
5 0
It’s 600 hope that helped you
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Computing if a computer can do one calculation in 0.0000000015 second, then the function t(n) = 0.0000000015n gives the time req
Lelechka [254]

Answer:

t(5,000,000,000) = 7.5 sec

Explanation:

A computer take 0.0000000015 sec to do a calculation.

Given a function t(n) = 0.0000000015n

where n represent the number of calculation.

We need to find the total time computer to do 5 billion calculations.

We plug n = 5 billion = 5,000,000,000

Total taken time t(n) =0.0000000015n

t(5,000,000,000) = (0.0000000015)*(5,000,000,000)

t(5,000,000,000) = 1.5*5

t(5,000,000,000) = 7.5 sec

That's the final answer.

I hope it will help you.



4 0
2 years ago
Vinh needs 420 points to have a b average in math. his scores so far are 88, 89, 79, and 77. what is the minimum score he can ma
vlabodo [156]
88 + 89 + 79 + 77 = 333. 420-333= 87. The minimum score he can get is 87
6 0
2 years ago
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Cuantos paquetes de 10 vasos ocupo para empacar 1367 vasos
SpyIntel [72]
137 paquetes de vasos, aunque el último nomas contiene 7 vasos se necesita el paquete para que no queden sin empacar
8 0
2 years ago
Quadrilateral $abcd$ is a trapezoid with $ab$ parallel to $cd$. we know $ab = 20$ and $cd = 12$. what is the ratio of the area o
alekssr [168]
Draw a diagram to illustrate the problem as shown below.

The area of triangle acb is
A₁ = (1/2)*20*h = 10h

The area of trapezoid abcd is
A₂ = (1/2)*(20+12)*h = 16h

The ratio A₁/A₂ is
A₁/A₂ = (10h)/(16) = 5/8

Answer:
The ratio of triangle acb to the area of trapezoid abcd is 5/8.

4 0
2 years ago
In a survey of men aged 20-29 in a certain country, the mean height is 73.4 inches with a standard deviation of 2.7 inches. Find
satela [25.4K]

Answer:

The minimum height in the top 15% of heights is 76.2 inches.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 73.4, \sigma = 2.7

Find the minimum height in the top 15% of heights.

This is the value of X when Z has a pvalue of 0.85. So it is X when Z = 1.04.

Z = \frac{X - \mu}{\sigma}

1.04 = \frac{X - 73.4}{2.7}

X - 73.4 = 1.04*2.7

X = 76.2

The minimum height in the top 15% of heights is 76.2 inches.

3 0
2 years ago
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