Draw the picture and label the
width = w
The length of the monitor is six times the quantity of five less than half its width:
length = 6(w/2-5)
length = 3w-30
Area = (length)*(width)
384=(3w-30)*(w)
384=3w^2-30w
Answer:
the dimensions of the monitor in terms of its width is:
384=3w^2-30w
Answer:
The solution to f(x) = t(x) is x = 2010
Option 3 is true.
Step-by-step explanation:
The first-year , second-year , and third-year enrollment values for a technical school are shown in the table below.
Year (x) First Year f(x) Second Year s(x) Third Year t(x)
2009 785 756 756
2010 740 785 740
2011 690 710 781
2012 732 732 710
2013 781 755 800
Now we will check each option.
Option 1: The solution to f(x) = s(x) is x = 2,009
In year 2009, f(x)=s(x)
But 785≠756
Thus, False
Option 2: The solution to f(x) = s(x) is x = 785
x represents year, but 785 it no year
Thus, False
Option 3: The solution to f(x) = t(x) is x = 2010
In year 2010, f(x)=t(x)=740
But 740=740
Thus, True
Option 4: The solution to f(x) = t(x) is x =740
x represents year, but 740 it no year
Thus, False
Answer:
Answer is x=328 .
Step-by-step explanation:
solution= (4x-16)^1/2=36
squaring both sides we get
4x-16=129
4x=1296+16
x=(1296+16)/4
x=328 .
Answer:
Time in minutes = 66 2/3
Time in hours = 1.11
Step-by-step explanation:
Problem:
Time taken by both machine to make 20 yo-yo
let the time taken be x minutes
Given
Time taken by machine A to make 1 yo-yo = 5 mins
No. of yo-yo made by machine A in x minutes = x/5
Time taken by machine B to make 1 yo-yo = 10 mins
No. of yo-yo made by machine B in x minutes = x/10
Total no. of yo-yo made by both the machine = x/5 + x/10 = (2*x+x)/10
Total no. of yo-yo made by both the machine = 3x/10
But given that together they made 20 yo -yo
Thus,
3x/10 = 20
=> x = 20*10/3 = 200/3
Thus, it took 66 2/3 minutes to make 20 yo-yo by both of them
In one hour there is 60 minutes
Time taken in Hours will be = 200/3*60 = 200/180 = 10/9 = 1 1/9= 1.11 hours
<h2>Hello!</h2>
The answer is:
The slant height is 13.43 m.
<h2>Why?</h2>
To solve the problem, we need to use the following equations to calculate the total surface area and the lateral surface area of right cone:
Where,
r, is the radius of the cone.
l, is the slant height of the cone.
We are given the following information:
So, calculating the area of the base(circle) in order to find the lateral surface area, we have:
Then, substituting the area of the base into the total surface area to calculate the surface area of the cone, we have:
Now, calculating the slant height, we have:
Substituting, we have:
Hence, we have that the slant height is 13.43 m.
Have a nice day!
