Answer:
a. average speed is 12km/hr
b. $5.50 dollars per hour
c. $0.46 per km
Step-by-step explanation:
a. 48km/4hrs = 12km/hr
b. $22/4hrs = $5.50/hr
c. $22/48km = $0.45833/km rounded to $0.46/km
Answer:
pano po yan hinde ko po alam
Step-by-step explanation:
paturo po
Answer:
apart from using the hoc to predict the college students gpa, some other variables can be used
1. the students intelligent quotient
2. ability to remember
3. study time
4. gym practice
Step-by-step explanation:
<u>1. the students intelligent quotient</u>
<u>gpa</u><u> </u>has a positive relationship with iq. they are both directly related. The more the iq of a a student, the greater is his ability to understand and have a good gpa. the slope will therefore be positive and be in an upward direction.
2. <u>ability to remember</u>
the gpa of students who have a good ability to remember but do not have a good grasp of the subject may not be high. the slope would be in a slightly upward direction
3. <u>study time</u>
gpa and practice have a positive relationship. the more a student studies, the more likelihood exists of having a better gpa. the slope would be upward bound.
4. <u>gym</u><u> </u><u>practice</u>
gpa and gym practice are not related so the slope would be in a downward direction.
when interpreting the direction of relationship after carrying out such an analysis, it is useful to watch out for the accompanying signs of the variables. if the sign of the beta coefficient is positive then a positive relationship with the dependent variable exists.
Answer:
a) P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90
a= μ-3.16*σ , b= μ+3.16*σ
b) P(Y≥ μ+3*σ ) ≥ 0.90
b= μ+3*σ
Step-by-step explanation:
from Chebyshev's inequality for Y
P(| Y - μ|≤ k*σ ) ≥ 1-1/k²
where
Y = the number of fish that need be caught to obtain at least one of each type
μ = expected value of Y
σ = standard deviation of Y
P(| Y - μ|≤ k*σ ) = probability that Y is within k standard deviations from the mean
k= parameter
thus for
P(| Y - μ|≤ k*σ ) ≥ 1-1/k²
P{a≤Y≤b} ≥ 0.90 → 1-1/k² = 0.90 → k = 3.16
then
P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90
using one-sided Chebyshev inequality (Cantelli's inequality)
P(Y- μ≥ λ) ≥ 1- σ²/(σ²+λ²)
P{Y≥b} ≥ 0.90 → 1- σ²/(σ²+λ²)= 1- 1/(1+(λ/σ)²)=0.90 → 3= λ/σ → λ= 3*σ
then for
P(Y≥ μ+3*σ ) ≥ 0.90
Answer:
56 cm
Step-by-step explanation:
We need ro find the GCD of these numbers. In finding the GCD, we list the multiples of the number, beginning with the smallest number. Here, the
The factors of 616=2*2*2*7*11
The factors of 448 =2*2*2*2*2*2*7
Common factors in both are 2*2*2*7=56
Therefore, the greatest possible length is 56 cm
