Answer:
The probability that the yellow M&M came from the 1994 bag is 0.07407 or 7.407%
Step-by-step explanation:
Given
Before 1995
(Br) Brown = 30%
(Y) Yellow = 20% =0.2
(R) Red = 20%
(G) Green =10% =0.1
(O) Orange = 10%
(T) Tan = 10%
After 1995
(Br) Brown = 13%
(Y) Yellow = 14% =0.14
(R) Red = 13%
(G) Green = 20%
= 0.2
(O) Orange = 16%
(Bl) Blue = 24%
Since there are two bags, let A be the bag from 1994, and B be the bag from 1996
Then let AY imply we drew a yellow M&M from the 1994 bag
AG implies we drew a green M&M from the 1994 bag
BY implies imply we drew a yellow M&M from the 1996 bag
BG implies we drew a green M&M from the 1996 bag
P(AY) =0.2
P (BY) = 0.14
P(AG) =0.1
P(BG) =0.2
Since the draws from the 1994 and 1996 bag are independent,
therefore

The draws can happen in either of the 2 ways in (1) and (2) above
therefore total probability E is given as
E =
For the yellow one to be from 1994, it implies that the event to be chosen is

Since the total probability is given as E=0.054
then 
Concluding statement: This is the condition for the Yellow one to come from 1994 and green from 1996 provided that they obey the condition from E
Answer:
1. V = D/t => D=Vt. as V = 16mph
D = 16t
2. Prya has been riding for t+½ hours
3. Prya has gone 12(t+½) miles
4. When Prya and Han meet
16t = 12t +6
4t = 6
t = 3/2 hours
.25
You just move the decimal forward 2 spaces
Since our sum is 62, and we have consecutive numbers being added, our range is most likely going to be from 10-20.
To further solve this problem easily, try finding 4 consecutive numbers with the ones place adding up to 12, 22, 32, 42, or any number that sums up to the 2 in the ones place.
Let's try 14, 15, 16, 17, since 4, 5, 6, and 7 sum up to a number with a 2 in the ones place.
14 + 15 = 29,
16 + 17 = 33.
33 + 29 is 62.
We have found the age of the friends, but we're looking for the oldest.
Our largest number is 17.
Your answer is 17 years old.
I hope this helps!
Where are the numbers so that people can help you