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Reptile [31]
2 years ago
5

A local school needs to paint the floor of its theater room, where the length of the floor, x, is at least 11 feet. The width of

the floor is 4 feet less than the length. It will have a stage and a closet, and the remaining area of the floor will be painted. The dimensions are shown in the diagram: rectangle with length of x ft and width of x minus 4 ft, right triangle inside labeled stage with height of x minus 4 ft and base of 8 ft, rectangle inside labeled closet with length of 7 ft and width of 3 ft, the rest of the rectangle is labeled floor Let A represent the painted area, in square feet, of the floor. Choose the correct equation to solve for area (A). A = x(x − 4) − (8)(x − 4) − 3(7) A = x(x − 4) + (8)(x − 4) + 3(7) A = x(x − 4) + 0.5(8)(x − 4) + 3(7) A = x(x − 4) − 0.5(8)(x − 4) − 3(7)
Mathematics
2 answers:
valentina_108 [34]2 years ago
8 0

Answer:

A = x(x − 4) − 0.5(8)(x − 4) − 3(7)

Step-by-step explanation:

x = length, making the width (x-4)

The stage closet will be (x-4)(8)(1/2)

The rectangle is 7(3)

That makes the painted area x(x-4) - 4(x-4)

So...

A = x(x − 4) − 0.5(8)(x − 4) − 3(7)

tigry1 [53]2 years ago
8 0

Answer:

D

Hope this helps

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If on a scale drawing 15 feet are represented by 10 inches then a scale of 1/10 inch represents how many feet
GenaCL600 [577]

A scale of \frac{1}{10} inches will represent \frac{3}{20} feet.

Step-by-step explanation:

According to scale drawing;

15 feet = 10 inches

1 inch = \frac{15}{10}=\frac{3}{2}\ feet

A scale of \frac{1}{10} inch will represent;

Multiplying both sides by

\frac{1}{10}*1=\frac{3}{2}*\frac{1}{10}\\\\\frac{1}{10}\ inches = \frac{3}{20}\ feet

A scale of \frac{1}{10} inches will represent \frac{3}{20} feet.

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2 years ago
"Our customer retention rate has decreased 10% from last quarter's goal of 250 consumers retained. We need to increase our curre
Lorico [155]
1. multiply 250 by 10% (250 * .1= 25)
2. Then subtract 25 from 250 (250 -25= 225)
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6 0
2 years ago
The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)
Lemur [1.5K]

Answer:

Cardiac output:F=0.055 L\s

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output:F=\frac{A}{\int\limits^T_0 {c(t)} \, dt} ---1

A = 3 mg

\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt

Do, integration by parts

[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}

[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}

[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}

Substitute the value in 1

Cardiac output:F=\frac{3}{54.49}

Cardiac output:F=0.055 L\s

Hence Cardiac output:F=0.055 L\s

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Answer:

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Step-by-step explanation:

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