123 lb * (0.4536 kg/lb) * 300mg/(kg · day)
= (123 * 0.4536 * 300) mg/day
= 16737.84 mg/day
16737.84 mg/day * 1g/(1000mg)
= 16.73784 g/day
Answer: The proportion of students spending at least 2 hours on social media equals 0.7257 .
Step-by-step explanation:
Given : The typical college freshman spends an average of μ=150 minutes per day, with a standard deviation of σ=50 minutes, on social media.
The distribution of time on social media is known to be Normal.
Let x be the number of minutes spent on social media.
Then, the probability that students spending at least 2 hours (2 hours = 120 minutes as 1 hour = 60 minutes) on social media would be:

Hence, the proportion of students spending at least 2 hours on social media equals 0.7257 .
Answer:
The distance the water is traveling and the time it took.
Step-by-step explanation:
The speed formula is s= d/t so I would guess that is what the question means.
(Sorry if I didn't take a lot of time to answer, it had caps so I would guess that you needed the answer fast. )