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2 years ago

ΔEFG ~ ΔLMN. Find LM.

Mathematics

2 answers:

bezimeni [28]2 years ago

7 0

The solution is 2.5. The problem can be solved using the proportion:

Vika [28.1K]2 years ago

6 0

EFG ~ LMN, if EF ~ LM, then whatever the number is for EF times whatever the others are multiplied by, you will get LM
for example:

FG (10) ~ MN (20)

if EF is (5), then LM is (10) (for you are multiplying by two.

Another example:

if FG is (100) ~ MN will be (200) (again for you are multiplying by two.

hope this helps

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What is the cube root of -729a9b6

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<u>ANSWER</u>

$\sqrt[3]{- 729{a}^{9} {b}^{6} } = - 9 {a}^{3} {b}^{2}$

<u>EXPLANATION</u>

We want to find the cube root of

$- 729 {a}^{9} {b}^{6}$

We express this symbolically as:

$\sqrt[3]{- 729 {a}^{9} {b}^{6} }$

The expression under the radical called the radicand.

We need to express this radical in exponential form using the property,

${x}^{ \frac{m}{n} } = \sqrt[n]{ {x}^{m} }$

Applying this rule gives us:

$\sqrt[3]{- 729 {a}^{9} {b}^{6} } = ({- 729 {a}^{9} {b}^{6}})^{ \frac{1}{3} }$

$\sqrt[3]{- 729{a}^{9} {b}^{6} } = ({- {9}^{3} {a}^{9} {b}^{6}})^{ \frac{1}{3} }$

Recall that

$({a}^{m} )^{n} = {a}^{mn}$

We apply this rule on the RHS to get,

$\sqrt[3]{- 729{a}^{9} {b}^{6} } = ({- {9}^{3 \times { \frac{1}{3} } } {a}^{9 \times { \frac{1}{3} } } {b}^{6 \times { \frac{1}{3} } }})$

This simplifies to

$\sqrt[3]{- 729{a}^{9} {b}^{6} } = - 9 {a}^{3} {b}^{2}$

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Jerry's Fish Shack claims that 16% of its employees are late to work once a week. The manager surveyed 25 employees and found th

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We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:

Null hypothesis: $p=0.16$

Alternative hypothesis: $p \neq 0.16$

$z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546$

$p_v =2*P(z>0.546)=0.585$

Step-by-step explanation:

Data given and notation

n=25 represent the random sample taken

$\hat p=0.2$ estimated proportion

$p_o=0.16$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:

Null hypothesis: $p=0.16$

Alternative hypothesis: $p \neq 0.16$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>0.546)=0.585$

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