490*x + 700*y ≤ 4000
It is ≤ as it can either be equal to 4000 per week or less than.
Footnote: Burritos are awesome
The question does not make sense.
The commutative property applies to addition and multiplication, not addition and subtraction.
The commutative property does not apply to subtraction or division because in those operations, the order of the numbers makes a difference, whereas in addition and subtraction the order does not make a difference.
For example:
Addition
5 + 4 = 9
4 + 5 = 9
5 + 4 = 4 + 5
Changing the order of the 4 and the 5 gives the same answer.
The commutative property does apply to addition.
Multiplication
5 * 4 = 20
4 * 5 = 20
5 * 4 = 4 * 5
Changing the order of the 4 and the 5 gives the same answer.
The commutative property does apply to multiplication.
Subtraction
5 - 4 = 1
4 - 5 = -1
5 - 4 is not equal to 4 - 5
Changing the order of the 4 and the 5 gives a different answer.
The commutative property does not apply to subtraction.
Division
5/4 = 1.25
4/5 = 0.8
1.25 is not equal to 0.8.
Changing the order of the 4 and the 5 gives a different answer.
The commutative property does not apply to division.
Answer:
(A) 0.15625
(B) 0.1875
(C) Can't be computed
Step-by-step explanation:
We are given that the amount of time it takes for a student to complete a statistics quiz is uniformly distributed between 32 and 64 minutes.
Let X = Amount of time taken by student to complete a statistics quiz
So, X ~ U(32 , 64)
The PDF of uniform distribution is given by;
f(X) = 
, a < X < b where a = 32 and b = 64
The CDF of Uniform distribution is P(X <= x) = 
(A) Probability that student requires more than 59 minutes to complete the quiz = P(X > 59)
P(X > 59) = 1 - P(X <= 59) = 1 - = 1 - 
= 
= 0.15625
(B) Probability that student completes the quiz in a time between 37 and 43 minutes = P(37 <= X <= 43) = P(X <= 43) - P(X < 37)
P(X <= 43) = 
= 
= 0.34375
P(X < 37) = 
= 
= 0.15625
P(37 <= X <= 43) = 0.34375 - 0.15625 = 0.1875
(C) Probability that student complete the quiz in exactly 44.74 minutes
= P(X = 44.74)
The above probability can't be computed because this is a continuous distribution and it can't give point wise probability.
Answer:
Option D (-4,7)
Step-by-step explanation:
we have
Square TUVW with vertices T(-6,1), U(-1,0), V(-2,-5), and W(-7,-4
<u><em>The question is</em></u>
Find out the coordinates of U'
Part a) Reflection: in the y-axis
we know that
The rule of the reflection of a point across the y-axis is
(x,y) -----> (-x,y)
so
U(-1,0) -----> U'(1,0)
Part b) Translation (x,y) —> (x-5,y+7)
That means ---> the translation is 5 units at left and 7 units up
so
U'(1,0) -----> U''(1-5,0+7)
U'(1,0) -----> U''(-4,7)
therefore
Option D (-4,7)
