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1 year ago

7

Zoe the goat is tied by a rope to one corner of a 15 by 25 meter rectangular barn in the middle of a large, grassy field. Over w

hat area of the field can Zoe graze if the rope is 10 meters

1 answer:

atroni [7]1 year ago

6 0

Answer: $78.55\ m^2$

Step-by-step explanation:

Given

The goat is tied by a rope to one corner of a rectangular field with length of rope 10 m.

Zoe can graze in an area equal to quadrant of circle with radius 10 m

Area of grazing is

$\Rightarrow \dfrac{1}{4}\times \pi r^2\\\\\Rightarrow \dfrac{\pi r^2}{4}\\\\\Rightarrow \dfrac{\pi \times 10^2}{4}=78.55\ m^2$

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A police helicopter is flying at 150 mph at a constant altitude of 0.5 mile above a straight road. The pilot uses radar to deter

natali 33 [55]

Answer:

a) (see attached picture)

b) d, h, velocity of helicopter, dd/dt

in the direction oposite to the movement of the helicopter.

Step-by-step explanation:

In order to solve this problem we must start by drawing a diagram that will represent the situation (see attached picture). As you may see, there is a right triangle being formed by the helicopter, the car and the graound. We can use this to build the equation we are going to use to model the problem.

$d^{2}=h^{2}+x^{2}$

we can use this equation to find the value of x at that very time, so we can do that by solving the equation for x, so we get:

$x=\sqrt{d^{2}-h^{2}}$

and substitute the given values:

$x=\sqrt{(1)^{2}-(0.5)^{2}}$

which yields:

x=0.866mi

we know that the height of the helicopter is going to be constant, so we rewrite the equation as:

$d^{2}=(0.5)^{2}+x^{2}$

$d^{2}=0.25+x^{2}$

Next, we can go ahead and differentiate the equation so we get:

$2d\frac{dd}{dt}=2x\frac{dx}{dt}$

which can be simplified to:

$d\frac{dd}{dt}=x\frac{dx}{dt}$

we can next solve the equation for dx/dt so we get:

$\frac{dx}{dt}=\frac{d}{x}*\frac{dd}{dt}$

so we can now substitue te provided values so we get:

$\frac{dx}{dt}=\frac{1}{0.866}*-190$

so we get:

$\frac{dx}{dt}=-219.40mph$

the negative sign means that the x-value is decreasing.

now, this problem deals with relative velocities, so we get that:

Velocity of car about the helicopter = Velocity of the car - Velocity of the helicopter. Or:

$V_{ch}=V_{c}-V_{h}$

so we can solve this for the actual velocity of the car, so we get:

$V_{c}=V_{ch}+V_{h}$

so we get:

$V_{c}=-219.40mph+150mph$

which yields:

$V_{c}=-69.4mph$

So it has a velocity of 69.4mph in a direction oposite to the helicopter's movement.

4 0

1 year ago

What values of c and d make the equation true? Assume x greater-than 0 and y greater-than-or-equal-to 0 StartRoot StartFraction

Maru [420]

Answer:

c = 1, d = 3

Step-by-step explanation:

4 0

2 years ago

Find: (4x2y3 + 2xy2 – 2y) – (–7x2y3 + 6xy2 – 2y)

const2013 [10]

Answer:

The coefficients are

11,-4 and 0

Step-by-step explanation:

We are given two algebraic expressions. We are subtracting the second from the first.

First one is

$4x^2y^3+2xy^2-2y$

Second expression is

$-7x^2y^3+6xy^2-2y$

The given expression

= $4x^2y^3+2xy^2-2y-(-7x^2y^3+6xy^2-2y)\\=4x^2y^3+2xy^2-2y+7x^2y^3-6xy^2+2y\\=11x^2y^3-4xy^2+0y$

The coefficients are

11,-4 and 0

7 0

1 year ago

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Farid is baking muffins, The recipe calls for 3/4 cup of sugar for a full batch. Farid is making 1/2 of a batch. Write an expres

Tems11 [23]

Answer:

y = 3/8x

or

3/8 cups of sugar for every 1/2 batch of muffins

Step-by-step explanation:

Since we are only making 1/2 of the full batch of muffins, we only need to use 1/2 the cups of sugar:

$\frac{3}{4} (\frac{1}{2} )= \frac{3}{8}$ cups of sugar.

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2 years ago

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Susan and Mark are standing at different places on a beach and watching a bird. The angles of elevation they make are 20º and 50

NemiM [27]

The answer is 1.952 km

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2 years ago

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