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Vladimir [108]
1 year ago
7

Zoe the goat is tied by a rope to one corner of a 15 by 25 meter rectangular barn in the middle of a large, grassy field. Over w

hat area of the field can Zoe graze if the rope is 10 meters
Mathematics
1 answer:
atroni [7]1 year ago
6 0

Answer: 78.55\ m^2

Step-by-step explanation:

Given

The goat is tied by a rope to one corner of a rectangular field with length of rope 10 m.

Zoe can graze in an area equal to quadrant of circle with radius 10 m

Area of grazing is

\Rightarrow \dfrac{1}{4}\times \pi r^2\\\\\Rightarrow \dfrac{\pi r^2}{4}\\\\\Rightarrow \dfrac{\pi \times 10^2}{4}=78.55\ m^2

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What is the domain and range of the equation y=500(1.08)^x
Marina CMI [18]
(x) is an element of a real number. This means it could be an integer, fraction or irrational number.

* As x approaches infinity, y approaches infinity.

* As x approaches minus infinity, y approaches 0.

-------------

Domain:

(x) is an element of a real number

Range:

y>0
6 0
2 years ago
A project’s critical path is composed of activities A (variance .33), B (variance .67), C (variance .33), and D (variance .17).
julia-pushkina [17]

Answer:

The standard deviation on the critical path = 0.834

Step-by-step explanation:

Variance of activity A (V_{1}) = 0.33

Variance of activity B (V_{2}) = 0.67

Variance of activity C (V_{3}) = 0.33

Variance of activity D (V_{4}) = 0.17

Thus the standard deviation on the critical path (\alpha ^{2}) = V_{1} ^{2} + V^2_{2} +  V^2_{3} + V^2_{4}

                                                                             \alpha ^{2}  = 0.33^{2} + 0.67^{2} + 0.33^{2} + 0.17^{2}

                                                                             \alpha ^{2} = 0.6956

                                                                             \alpha = 0.834

The standard deviation on the critical path = 0.834

4 0
2 years ago
the flag of the bahamas includes an equilateral triangle. the perimeter of the triangle is p=3s, where s is the side length. use
padilas [110]

Answer:

345

Step-by-step explanation:

3!

7 0
2 years ago
in any given year a factory has a 10% probability of having a serious accident. about every how many years might the factory exp
Likurg_2 [28]

Years for one serious accident is 10 year

<u>Given:</u>

Probability of having a serious accident = 10% every year

P(serious accident) = 0.1

Number of years = n

<u>Computation:</u>

Years for one serious accident = 1 / Probability of having a serious accident

Years for one serious accident = 1 / P(serious accident)

Years for one serious accident = 1 / 0.1

Years for one serious accident = 10 year

Learn more:

brainly.com/question/23044118?referrer=searchResults

5 0
1 year ago
(b) A department store has 7,000 charge accounts. The comptroller takes a random sample of 36 of
galben [10]

Answer:

a.0.8664

b. 0.23753

c. 0.15866

Step-by-step explanation:

The comptroller takes a random sample of 36 of the account balances and calculates the standard deviation to be N42.00. If the actual mean (1) of the account balances is N175.00, what is the probability that the sample mean would be between

a. N164.50 and N185.50?

b. greater than N180.00?

c. less than N168.00?

We solve the above question using z score formula

z = (x-μ)/σ/√n where

x is the raw score,

μ is the population mean = N175

σ is the population standard deviation = N42

n is random number of sample = 36

a. Between N164.50 and N185.50?

For x = N 164.50

z = 164.50 - 175/42 /√36

z = -1.5

Probability value from Z-Table:

P(x = 164.50) = 0.066807

For x = N185.50

z = 185.50 - 175/42 /√36

z =1.5

Probability value from Z-Table:

P(x=185.50) = 0.93319

Hence:

P(x = 185.50) - P(x =164.50)

= 0.93319 - 0.066807

= 0.866383

Approximately = 0.8664

b. greater than N180.00?

x > N 180

Hence:

z = 180 - 175/42 /√36

z = 5/42/6

z = 5/7

= 0.71429

Probability value from Z-Table:

P(x<180) = 0.76247

P(x>180) = 1 - P(x<180) = 0.23753

c. less than N168.00?

x < N168.

z = 168 - 175/42 /√36

z = -7/42/6

z = -7/7

z = -1

Probability value from Z-Table:

P(x<168) = 0.15866

4 0
1 year ago
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