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Alex787 [66]
2 years ago
15

FWML is a parallelogram. Find the values of x and y. Solve for the value of z, if z=x−y

Mathematics
1 answer:
Dima020 [189]2 years ago
4 0

Answer:

x=5

y=8

z=-3

Step-by-step explanation:

We have been given a parallelogram. We are asked to solve for the values of x and y.

We know that opposite sides of parallelogram are equal, so we can set equation as:

3x-3=x+7

3x-x-3=x-x+7

2x-3=7

2x-3+3=7+3

2x=10

\frac{2x}{2}=\frac{10}{2}

x=5

Similarly, we will solve for y.

2y-6=y+2

2y-y-6=y-y+2

y-6=2

y-6+6=2+6

y=8

To solve for z, we will subtract y from x as:

z=x-y\\z=5-8\\z=-3

Therefore, the value of z is negative 3.

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Answer:

<h3>- The ratio of the measure of central angle PQR to the measure of the entire circle is One-eighth. </h3><h3>- The area of the shaded sector depends on the length of the radius. </h3><h3>- The area of the shaded sector depends on the area of the circle</h3>

Step-by-step explanation:

Given central angle PQR = 45°

Total angle in a circle = 360°

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\theta = central angle (in degree) = 45°

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Area of the sector

= \frac{45}{360}*\pi (6)^{2}\\ = \frac{1}{8}*36 \pi\\  = 4.5\pi units^{2}

<u>The ratio of the shaded sector is 4.5πunits² not 4units²</u>

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Since Area of the circle = πr²

Area of the circle = 36πunits²

The ratio of the area of the shaded sector to the area of the circle = \frac{4.5\pi }{36 \pi } = \frac{1}{8}

For length of an arc

= \frac{45}{360}*2\pi r\\= \frac{45}{360}*2\pi (6)\\= \frac{45}{360}*12 \pi \\= \frac{12\pi }{8} \\= \frac{3\pi }{2} units

ratio of the length of the arc to the area of the circle = \frac{\frac{3\pi}{2} }{36\pi} = \frac{3}{72} =\frac{1}{24}

It is therefore seen that the ratio of the area of the shaded sector to the area of the circle IS NOT equal to the ratio of the length of the arc to the area of the circle

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