Question

You launch a water balloon. The function h=-0.08t^2+1.6t+2 models the height h (in feet) of the water balloon after t seconds. What is the initial height of the balloon?

Answer 1

Answer:

The initial height of the balloon is 2 feet.

Step-by-step explanation:

The height of the balloon in feet after t seconds is given by the following equation:

$h(t) = -0.08t^{2} + 1.6t + 2$

What is the initial height of the balloon?

This is h when t = 0, that is, h(0). So

$h(0) = -0.08*0^{2} + 1.6*0 + 2 = 2$

The initial height of the balloon is 2 feet.