Answer:
A) p = 
d
Step-by-step explanation:
20(which is d) x = 2 (which is p)
cross checking always helps!
The zeros are the values of t for which f(t) = 0.
i.e. <span>-16t^2 + 96t = 0
16</span>t^2 - 96t = 16t(t - 6)
16t = 0 or t - 6 = 0
t = 0 or t = 6
Therefore, the zeros are 0, 6
The time taken for the ball to hit the ground is the value of t when f(t) = 0.
i.e. t = 6.
Answer: the value of the car will be about $12634
Step-by-step explanation:
We would apply the formula for exponential decay which is expressed as
A = P(1 - r)^ t
Where
A represents the value of the car after t years.
t represents the number of years.
P represents the initial value of the car.
r represents rate of decay.
From the information given,
P = $22000
r = 10.5% = 10.5/100 = 0.105
t = 5 years
Therefore
A = 22000(1 - 0.105)^5
A = 22000(0.895)^5
A = $12634
Precision is a measure of how close a value is to the
ideal value. In this case, we calculate the difference to know what is the
closest to 4 g:
4.05 – 4 = 0.05
3.98 – 4 = -0.02
4.021 – 4 = 0.021
We can see that the value of 3.98g has the lowest
difference and is therefore the closest to 4g. Hence the most precise is:
<span>3.98 g</span>
Answer: 64 %
Step-by-step explanation:
Assume attendance last year to be equal to "x"
- An increase in percentage sees us add the percentage amount to 100.
- A decrease in percentage sees us subtract the percentage amount from 100.
Projected attendance = ((100+25)/100) * x = 1.25x
Actual attendance = ((100-20)/100) * x = 0.80x
Hence ratio of a actual to projected attendance = 0.80x/1.25x = 0.64
Convert into percentage = 0.64 * 100 = 64 %
