See attached picture and check solution below.
We are given with the following values:
A = length of transmission line = 96ft
B = length of shadow = 72 feet
C = distance of ladder to base of transmission line = 66 feet
Solve for angle created between the wire and tip of the shadow:
tan x = opposite/ adjacent
tan x = 96 feet / 72 feet
x = 53.13°
Solving for the height of the ladder:
tan x = Ladder length / (72-66)
tan 53.13° * (72-66) = ladder length
ladder length = 8 feet
The answer is letter "B" which is 8 feet.
We are given the equation:
<span>Z(q) = 4q + ½ --->
1</span>
The equation for z(u + 1/2) is obtained by
substituting q with u + ½ in the equation, therefore we can say that:
<span>q = u + ½ --->
2</span>
Substituting this value into equation # 1:
Z = 4 (u + ½) + ½ = z (u + 1/2)
4 u + 2 + ½ = z (u + 1/2)
<span>Since it was given that z (u +
1/2) = ½ then,</span>
4 u + 2 + ½ = ½
4 u + 2.5 = 0.5
4 u = -2
u = -1/2 (ANSWER)
<span> </span>
Answer:
1) ΔCBF ≅ ΔCDF by (SSS)
2) ΔBFA ≅ ΔDFE by (SAS)
3) ΔCBE ≅ ΔCDA by (HL)
Step-by-step explanation:
1) Since BC ≅ DC and DF ≅ BF where CF ≅ CF (reflective property) we have;
ΔCBF ≅ ΔCDF by Side Side Side (SSS) rule of congruency
2) Since DF ≅ BF and FA ≅ FE where ∠DFE = ∠BFA (alternate angles)
Therefore;
ΔBFA ≅ ΔDFE by Side Angle Side (SAS) rule of congruency
3) Since FA ≅ FE and DF ≅ BF then where EB = FE + BF and AD = FA + DF
Where:
EB and AD are the hypotenuse sides of ΔCBE and ΔCDA respectively
We have that;
EB = AD from FE + BF = FA + DF
Where we also have BC ≅ DC
Where:
BC and DC are the legs of ΔCBE and ΔCDA respectively
Then we have the following relation;
ΔCBE ≅ ΔCDA by Hypotenuse Leg (HL).
For this case, the parent function is given by:

We apply the following transformations:
Vertical translations:
Suppose that k> 0
To graph y = f (x) + k, move the graph of k units upwards:
For k = 9 we have:

Horizontal translations:
Suppose that h> 0
To graph y = f (x-h), move the graph of h units to the right
For h = 4 we have:

Answer:
The function g (x) is given by:

Answer:
It will cost $427.04 to paint deck and it will cost 958.485 to add fencing around deck
Step-by-step explanation:
Diameter of swimming pool = 27 feet
Radius of pool r=
Surrounding the pool is a deck that extends 5 feet from the edges of the pool
Outer radius R = 13.5+5=18.5
Area of deck = Outer area - Inner area
Area of deck =
Area of deck = 
Area of deck = 
Cost of painting 1 sq.feet = $0.85
Cost of painting 502.4 sq.feet = 
Perimeter of deck = 
Cost of fencing 1 foot = $8.25
Cost of fencing 116.18 foot = 
Hence it will cost $427.04 to paint deck and it will cost 958.485 to add fencing around deck